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egoroff_w [7]
3 years ago
13

What is the mass of a titanium alloy that has a heat of fusion of 422.5 joules/gram and requires 2,960 joules of energy to melt

completely? Use the formula Q = mHf. A. 0.143 g B. 1.43 g C. 7.01 g D. 7.81 g
Chemistry
1 answer:
romanna [79]3 years ago
7 0

Answer:- Mass of the titanium alloy is 7.01 g, choice C is correct.

Solution:- The heat of fusion is given as 422.5 joules per gram and it also says that 2960 joules of heat is required to melt the metal completely.

The suggested equation is, Q=mH_f

where Q is the heat energy, m is the mass and Hf is the heat of fusion.

Since, we are asked to calculate the mass, the equation could be written as:

m=\frac{Q}{H_f}

Let's plug in the values in it:

m=\frac{2960J}{\frac{422.5J}{g}}

m = 7.01 g

So, the mass of the titanium alloy is 7.01 g, choice C is correct.

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What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
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Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

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Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

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Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

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This table has information about the heat of fusion and the heat of vaporization of different substances. A 3-column table with
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<h3>Further explanation</h3>

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