Answer: Molarity of 
anions in the chemist's solution is 0.0104 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= moles of solute
= volume of solution in ml = 100 ml
Now put all the given values in the formula of molarity, we get
Therefore, the molarity of solution will be 
As 1 mole of 
gives 2 moles of
Thus 
moles of gives =
Thus the molarity of anions in the chemist's solution is 0.0104 M
Answer:
if you did it would probably make it bigger...
Explanation:
:)
The answer will be b. membrane.
Formula M1V1 =M2V2
1.5 * 100 = M2 *300
M2 = 1.5*100/300= 0.5.
Answer: the molarity is 0.5M.
Answer:
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆
Explanation:
The osmotic pressure of a compound is calculated using the following expression:
π = MRT (1)
This expression is used when the substance is nonelectrolyte. If the solution is electrolyte solution then we need to count the van't hoff factor into the expression so:
π = MRTi (2)
Now, we have 4 solutions here, only two of them are electrolyte solution, this means that these solutions can be dissociated into separate ions. These solutions are LiCl and CaCl₂. It can be shown in the following reactions:
LiCl -------> Li⁺ + Cl⁻ 2 ions (i = 2)
CaCl₂ ---------> Ca²⁺ + 2Cl⁻ 3 ions (i = 3)
The methanol (CH₃OH) and glucose (C₆H₁₂O₆) are non electrolyte solutions, therefore they are not dissociated. So, let's use expression (1) for methanol and glucose, and expression (2) for the salts:
CaCl₂: π = 1 * 3 * RT = 3RT
CH₃OH: π = 2 * RT = 2RT
C₆H₁₂O₆: π = 1 * RT = 1RT
LiCl: π = 1 * 2 * RT = 2RT
Finally with these results we can conclude that the decreasing order of these solutions according to their osmotic pressures are:
<h2>
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆</h2>
