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3 years ago

7

A flagpole is 25 feet tall. A rope is tied to the top of the flagpole and secured to the ground 16 feet from the base of the fla

gpole. Draw the situation and then use the Pythagorean theorem to estimate the length of the rope to the nearest integer value

1 answer:

Lerok [7]3 years ago

8 0

As for the drawing, help yourself.

P. theorem -- a^2 + b^2 = c^2
a = 25
b = 16

so 25^2 + 16^2 = c^2
c^2 = 881
c = sqrt881

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a photographer shines a camera light at a particular painting forming an angle of 50 degrees with a camera platform at the light

umka2103 [35]

Answer:

The painting is 42.13 feet above the platform

Step-by-step explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting. i.e. AC

So, we will use trigonometric ratio :

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

$sin50^{circ} = \frac{AC}{AB}$

$sin50^{circ} = \frac{AC}{55}$

$0.766*55 = AC$

$42.13= AC$

Thus the painting is 42.13 feet above the platform

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3 years ago

Given: BA = 6 feet

bogdanovich [222]

The answer is definitely not 7.777777

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3 years ago

What is 145.4 - 140.02 ?

Assoli18 [71]

Answer:

5.38

Step-by-step explanation:

145.4 - 140.02 = 5.38

3 0

3 years ago

Read 2 more answers

I need help with this please help asap

kaheart [24]

Step-by-step explanation:

4^5 (-2)^9/4^8 (-2)^3

= 4^(5 - 8) (-2^(9 - 3))

= 4^-3 (-2^6)

= (-2)^6/4^3

1). (-2)^a/4^b

a = 6, b = 3

2). c/d

c = -2, d = 4

6 0

3 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago