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VashaNatasha [74]
3 years ago
13

Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons?

Chemistry
2 answers:
german3 years ago
6 0
Phosphorus is the element among the elements given in the question that if <span>combined with chlorine, will have the greatest attraction for the chlorine electrons. The correct option among all the options given in the question is the second option or option "b" and the fact is that you have chosen correctly. </span>
Sergio [31]3 years ago
6 0

The ANSWER is b)P

.....................P.......................


Phosphorous

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Which action do researchers take to make advances in science?
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3 0
3 years ago
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Niven wants to calculate the mass of mgo that is produced by burning of 28.0g of mg. What is the first step in nivens calculatio
babymother [125]

Answer: -

The experiment Niven is doing is burning of Mg.

The first step would be finding the molar mass of MgO

Atomic mass of Mg = 24 g

Atomic mass of Oxygen = 16 g

Molar mass of MgO = 24 x 1 + 16 x 1 = 40 g

The balanced chemical equation for this reaction is

2 Mg + O2 -- > 2MgO

From the balanced equation we see that

2 Mg gives 2 MgO

2 x24 g of Mg O gives 2 x 40 g of MgO.

28g of MgO gives \frac{2 x 40 gram x 28 gram }{2 x 24 gram}

= 46.66 g of MgO.

8 0
3 years ago
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The process that changes a solid directly into a gas is called sublimation. A solid that begins with a mass of 450 g will sublim
cluponka [151]
The mass is conserved, so it stays the same, 450g
5 0
3 years ago
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A sample of gas occupies a volume of 27 mL at a temperature of 161K. What is the volume of the temperature if raised to 343K?
d1i1m1o1n [39]

Answer: The  volume is 57.52 mL if the temperature if raised to 343K.

Explanation:

Given: V_{1} = 27 mL,       T_{1} = 161 K

V_{2} = ?,        T_{2} = 343 K

According to Charles law, at constant pressure the volume of an ideal gas is directly proportional to temperature.

Formula used is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{27 mL}{161 K} = \frac{V_{2}}{343 K}\\V_{2} = 57.52 mL

Thus, we can conclude that volume is 57.52 mL if the temperature if raised to 343K.

4 0
3 years ago
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