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cupoosta [38]
3 years ago
12

In what direction does energy move​

Chemistry
2 answers:
Arlecino [84]3 years ago
7 0

In every direction guyz but conventionally it moves from higher potential to lower potential

julia-pushkina [17]3 years ago
5 0

Answer:

energy move from hot toward cold

Explanation:

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R u a gurl hmmmmmmmmmm
posledela

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. A compound is composed of 2 atoms of Copper, 1 atom of Sulfur and 4 atoms of Oxygen. What
Dennis_Churaev [7]

The chemical formula for this compound : Cu₂SO₄-Copper(I) sulfate

<h3>Further explanation</h3>

Given

2 atoms of Copper, 1 atom of Sulfur and 4 atoms of Oxygen.

Required

The chemical formula

Solution

The number of atoms forming a compound is usually indicated from the subscript in the formula

From the problem it can be seen that the compound has:

2 atoms of Cu, 1 atom of S, and 4 atoms of O

So the formula:

<em>Cu₂SO₄</em>

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What is the science of stratigraphy
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Which of the following is a possible Noble gas notation?
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calculate the freezing point of 3.46 gram of a compound X in 160 gram of benzene when a separate sample of X was vaporized it's
Temka [501]

Answer: The freezing point of 3.46 gram of a compound X in 160 gram of benzene is 4.38^0C

Explanation:

The relation of density and molar mass is:

d=\frac{PM}{RT}

where

d = density = 3.27 g/ L

P = pressure of the gas  = 773 torr = 1.02 atm   (760 torr = 1atm)

M = molar mass of the gas  = ?

T = temperature of the gas = 116^0C=(116+273)K=389K

R = gas constant  = 0.0821Latm/Kmol

M=\frac{dRT}{P}=\frac{3.27g/L\times 0.0821Latm/Kmol\times 389K}{1.02atm}=102.3g/mol

The relation of depression in freezing point with molality:

\Delta T_f=k_f\times m

\Delta T_f = depression in freezing point = T_f^0-T_f = 5.45-T_f

k_f = freezing point constant  = 5.1

m = molality = \frac{\text {moles of X}}{\text {weight of solvent in kg}}=\frac{3.46\times 1000}{102.3\times 160}=0.21

5.45-T_f=5.1\times 0.21

T_f=4.38^0C

Thus the freezing point of 3.46 gram of a compound X in 160 gram of benzene is 4.38^0C

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