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3 years ago

Andrew and Jeffrey walk together. When Andrew walks 3

Chemistry

1 answer:

atroni [7]3 years ago

4 0

Answer: 250 steps

Explanation:

The data we were given;

When Andrew walks 3 steps; Jeffrey walks 5 steps to catch up

That's is to say

Andrew's 3 steps = Jeffrey's 5 steps

Now Andrew's 150 steps = Jeffrey's X steps

So we have to find the number of steps (X) Jeffrey would have to take to catch up with Andrew.

3 = 5

150 = X

3X = 150 × 5

X = (150 × 5) / 3

X = 750 / 3

X = 250

Therefore Jeffrey would need 250 steps to catch up with Andrew.

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zhuklara [117]

Answer:

0.2 is conpound Co2 STP.

Explanation:

on combustion of 0.2 gm of organic compound gave 0.147g of CO2, 0.12g of H2O and 74.6 ml of nitrogen gas at STP. Find emperical formula of compound.?

5 0

2 years ago

A 2.1−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calcula

Fiesta28 [93]

Answer:

Total worth of gold in the ocean = $5,840,000,000,000,000

Explanation:

As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.

Therefore, In 1 L of ocean water there will be,

(4.0 x 10^-10)/0.0021

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So in 1.5 x 10^-21 L of ocean water, there will be

(1.9045 x 10^-7) * (1.5 x 10^-21)

= 2.857 x 10^14 g of gold in the ocean.

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20.44 * (2.857 x 10^14)

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8 0

3 years ago

1. Mg2+ and Ca2+ are in the same group on the periodic table. In terms of electronic

finlep [7]

Answer:

Se detailed explanation.

Explanation:

Hello,

In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:

- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.

- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.

- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.

- Their electron configurations are:

$Ca^{20}=1s^2,2s^2,2p^6,3s^3,3p^6,4s^2\\\\Mg^{12}=1s^2,2s^2,2p^6,3s^2$