Answer:
Work done on the system is zero , hence no work is done since the process is <u>isochoric.</u> There is no work done if the volume remains unchanged. (Though the temperature rises, work is only accomplished when the volume of the gas changes.)
Explanation:
ISOCHORIC PROCESS - An isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, is a thermodynamic process in which the volume of the closed system undergoing the process remains constant through the process. The heating or cooling of the contents of a sealed, inelastic container is an example of an isochoric process. The thermodynamic process is the addition or removal of heat, the closed system is established by the isolation of the contents of the container, and the constant-volume condition is imposed by the container's inability to deform. It should be a quasi-static isochoric process in this case.
<u>Hence , the work done in the system is zero.</u>
Answer:
Substances that absorb energy in the form of heat are
b)endothermic.
hope it helps :)
Is bubble chamber one of your choices? Bubble chamber sounds like a good fit for the question.
Explanation:
<em>Potas</em><em>sium</em><em> </em><em>has</em><em> </em><em>an</em><em> </em><em>atomi</em><em>c</em><em> </em><em>radii</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>greate</em><em>r</em><em> </em><em>t</em><em>han</em><em> </em><em>t</em><em>hat</em><em> </em><em>of</em><em> </em><em>lithiu</em><em>m</em><em> </em><em>th</em><em>at</em><em> is</em><em> </em><em>why</em><em> </em><em>pot</em><em>assium</em><em> </em><em>is</em><em> </em><em>more</em><em> </em><em>reactiv</em><em>e</em><em> </em><em>than</em><em> </em><em>lithi</em><em>um</em><em>.</em>
<em>tHx</em><em> </em><em>fOr</em><em> pOinTs</em><em>.</em><em>.</em><em>.</em>
NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)
You want to calculate the mass of NaH, I assume. Otherwise, the question isn't clear. It simply says calculate the mass(??)
So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr. But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas. So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.
PV = nRT
n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)
n = 0.0385 moles H2
moles NaH needed = 0.0385 moles H2 x 1 mole NaH/mole H2 = 0.0385 moles NaH required
mass of NaH needed = 0.0385 moles x 24 g/mole = 0.925 g NaH
Brainliest Please :)