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avanturin [10]
4 years ago
11

Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons?

Chemistry
1 answer:
Sedbober [7]4 years ago
5 0

Answer:

That would be more

Explanation:

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The decay rate of a radioactive isotope can be increased by increasing the
kumpel [21]
<span>Size of the sample there you go hope it helps :>

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8 0
4 years ago
Why it is important for humans to conserve freshwater?
aniked [119]

Answer:

Conserving water can help alleviate the effects of water shortages in any given community. Water use drains other resources. Using in-house water resources requires energy to deliver the water to your home. This energy-use increases when you use hot water since a lot of energy goes into heating.

Explanation:

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6 0
2 years ago
What evidence did dalton have that atoms actually exist?
likoan [24]
<span>Dalton noted that the chromium oxide molecules that he was studying had masses of oxygen that were not the same: he found that there were constant ratios to these mass differences, however, so there had to be some sort of "units" (atoms) making up the ratios of these particles.</span>
5 0
3 years ago
The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
viktelen [127]
The exact molecular mass for butane (C4H10) is 
12.0096*4+1.0079*10=58.1174  which is 58.1 to 3 significant figures.

Proportion of carbon in the compound
12.0096*4: 58.1174
=>
48.0384 : 58.1174

The mass of carbon in 2.50 grams of butane can be obtained by proportion, namely
Mass of carbon
= 2.50 * (48.0384/58.1174)
= 2.0664
= 2.07 g (approximated to 3 significant figures)

4 0
3 years ago
Calculate the number of mg of Mn2+ left
soldi70 [24.7K]

Answer:

1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

Explanation:

The reaction that takes place is:

Mn⁺² + S⁻² ⇄ MnS(s)  

ksp = [Mn⁺²] [S⁻²]

If the pksp of MnS is 13.500, then the ksp is:

ksp=10^{-13.500}=3.1623*10^{-14}

From the problem we know that [S⁻²] = 0.0900 M

We use the ksp to calculate [Mn⁺²]:

3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M

[Mn⁺²] = 3.514 * 10⁻¹³ M.

Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:

3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.

6 0
3 years ago
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