Answer:
F1+ is the one that violates the octet rule
Explanation:
F1+ does not end up having 8 electrons in its valence shell, and there for violates the octet rule, for an atom to comply with the octet rule its charge must reflect the number of electrons it needs to gain or lose to make an octet, but F1+'s charge does not reflect the number of electrons it needs to be stable or have an electron configuration of a noble gas
The question is incomplete, the complete question is shown in the image attached
Answer:
3-isopropyl-1-hexyne
Explanation:
Organic compounds can be named from the structure of the compound. The name reveals the arrangement of atoms and bonds in the molecule.
If we look at the compound in the question, we will notice that the parent chain contains six carbon atoms, the triple bond is located at position 1 and the isopropyl substituent is attached to carbon 3.
Hence the proper name of the compound becomes, 3-isopropyl-1-hexyne.
The concentration of lead nitrate is 3.48 M.
<u>Explanation:</u>
The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,
Here mass of Pb(NO₃)₂ is 380 g
Molar mass of Pb(NO₃)₂ is 331.2 g/mol
Number of moles = 
= 
= 1.15 moles
Volume in Litres = 330 ml = 0.33 L
Molarity = 
= 3.48 mol/L or 3.48 M
So the concentration of lead nitrate is 3.48 M.
Answer:
0.13 M
Explanation:
The reaction equation is;
NaOH(aq) + KHC8H4O4(aq) ------> KNaC8H4O4(aq) + H2O(l)
Molar mass of KHP = 204.22 g/mol
Amount of KHP= mass/ molar mass = 0.3365 g/204.22 g/mol = 1.65 × 10^-3 moles
n= CV
Where;
C= concentration
V= volume in dm^3
n= number of moles
C= n/V = 1.65 × 10^-3 moles × 1000/250 = 6.6 × 10^-3 M
If 1 mole of KHP reacts with 1 mole of NaOH
1.65 × 10^-3 moles of KHP will react with 1.65 × 10^-3 moles of NaOH
From
n= CV
We have that only 12.44 ml of NaOH reacted
C= n/V = 1.65 × 10^-3 moles × 1000/12.44
C= 0.13 M
At the equivalence point, the KHP solution turned light pink.
<u>Answer:</u>
<u>Balancin</u>g is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient and the subscript
For example
contains
5 × 1 = 5,Ca atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example
we multiply coefficient
subscript
number outside the bracket.......... to find the number of atoms
(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So
3 × 3 = 9, Ca atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
So
Let us balance the equation given

(Unbalanced)
Reactant side - Number of atoms of each element - Product side
1 - Sb - 1
2 - Cl - 3
So we have on the product side odd number of Cl to convert to even number, multiply
by 2
The equation changes to

Reactant side - Number of atoms of each element - Product side
1 - Sb - 2
2 - Cl - 6
Multiplying Sb by 2 and 

The equation is balanced now!!!!
Reactant side - Number of atoms of each element - Product side
2 - Sb - 2
6 - Cl - 6
Balanced.