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algol13
3 years ago
8

Convert 56.78 grams of Ca(OH)_2 to moles

Chemistry
1 answer:
ki77a [65]3 years ago
6 0

Answer: 0.77 mole

Explanation:

Atomic mass of Ca = 40g/mol

Atomic mass of O = 16g/mol

Atomic mass of H = 1

Therefore,

1 mole of Ca(OH)_2 contains

40+[16+1]2

= 40+34

=74g/mole

Hence,

1 mole of Ca(OH)_2 = 74g

Let x mole of Ca(OH)_2 = 56. 78

x = 56.78/74

x = 0.77 mole

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nekit [7.7K]
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Tc-99 is also a radioactive element. It's half-life is 2,11,000 years. Upon radioactive decay, it emits beta particles and gets converted into stable compound Ruthenium-99

This process of radioactive decay is shown below.
99 43Tc    →       99 44Ru     +     0 -1e
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3 years ago
3. What is the molar mass of O2? Round to nearest whole number.<br> 8<br> O<br> 16<br> 32<br> 64
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5 0
3 years ago
Calculate the mass of sodium phosphate in aqueous solution to fully react with 37 g of chromium nitrate(III) an aqueous solution
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Answer:

41 g

Explanation:

The equation of the reaction is;

Cr(NO3)3(aq)+Na3PO4(aq)=3NaNO3(s)+CrPO4(aq)

Number of moles of chromium nitrate = 37g/ 146.97 g/mol = 0.25 moles

1 mole of sodium phosphate reacts with 1 mole of chromium nitrate

x moles of sodium phosphate react as with 0.25 moles of chromium nitrate

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4 0
3 years ago
Suppose 50.0g of silver nitrate is reacted with 50g of hydrochloric acid producing silver chloride and a mixture of other produc
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Answer:

53.6 grams of silver chloride was produced.

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This also means that total mass on the reactant side must be equal to the total mass on the product side.

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Mass of silver chloride = x

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[te]50.0 g+50.0 g=x+46.4 g[/tex]

x=50.0 g+50.0 g - 46.4 g = 53.6 g

53.6 grams of silver chloride was produced.

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What energy is required to remove the remaining electron from singly ionized helium?
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1 year ago
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