The differences in the properties of diamond and graphite is as a result of how their particles are arranged in space. This space arrangement leads to distinct crystal structures for the two compounds. In diamond, the carbon atoms are arranged in tetrahedral shape while in graphite the carbon atoms arrayed in planes.
Hope this helps :)
To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.
n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
n = 0.40 mol N2
At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:
V = nRT / P
V = 0.40 x 8.314 x 293.15 / 102.7 x 10^3
V = 9.49 x 10^-3 m^3 or 9.49 L
Nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷
Answer:
See explaination
Explanation:
The invariant mass of an electron is approximately9. 109×10−31 kilograms, or5. 489×10−4 atomic mass units. On the basis of Einstein's principle of mass–energy equivalence, this mass corresponds to a rest energy of 0.511 MeV.
Check attachment for further solution to the exercise.
The trough and the hill part
