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Dvinal [7]
3 years ago
11

Jaquez earns money by doing yard work. It takes her an average of 3 hours to pull weeds and an average of 2.5 hours to mow the l

awn. She can work no more than 8 hours a day. She charges $50 to weed and $65 to mow the lawn. She needs to cover her expenses of $120 to make a profit. Write a system of inequalities that would help determine how many flowerbeds and lawns he could complete on a given day. (Note – you do not need to solve, just write the system and label the variables you use).

Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Let x = number of hours to pull weed in a day

Let y = number of hours to now lawn in a day

It takes her an average of 3 hours to pull weeds and an average of 2.5 hours to mow the lawn. She can work no more than 8 hours a day.

This means

3x + 2.5y is lesser than/ equal to 8

She charges $50 to weed and $65 to mow the lawn.

This means she charges

50x +65y

She needs to cover her expenses of $120 to make a profit. This means she needs to earn an amount greater than or equal to $120

50x + 65y greater than or equal to 120

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Harlamova29_29 [7]

Answer:

\huge{\purple {r= 2\times\sqrt[3]3}}

\huge 2\times \sqrt [3]3 = 2.88

Step-by-step explanation:

  • For solid iron sphere:
  • radius (r) = 2 cm (Given)

  • Formula for V_{sphere} is given as:

  • V_{sphere} =\frac{4}{3}\pi r^3

  • \implies V_{sphere} =\frac{4}{3}\pi (2)^3

  • \implies V_{sphere} =\frac{32}{3}\pi \:cm^3

  • For cone:
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  • Let r = 3x & h = 4x

  • Formula for V_{cone} is given as:

  • V_{cone} =\frac{1}{3}\pi r^2h

  • \implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)

  • \implies V_{cone} =\frac{1}{3}\pi (36x^3)

  • \implies V_{cone} =12\pi x^3\: cm^3

  • It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
  • \implies V_{cone} = V_{sphere}

  • \implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}

  • \implies 12x^3= \frac{32}{3}

  • \implies x^3= \frac{32}{36}

  • \implies x^3= \frac{8}{9}

  • \implies x= \sqrt[3]{\frac{8}{3^2}}

  • \implies x={\frac{2}{ \sqrt[3]{3^2}}}

  • \because r = 3x

  • \implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}

  • \implies r=3\times 2(3)^{-\frac{2}{3}}

  • \implies r= 2\times (3)^{1-\frac{2}{3}}

  • \implies r= 2\times (3)^{\frac{1}{3}}

  • \implies \huge{\purple {r= 2\times\sqrt[3]3}}
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  • log r = log (2\times \sqrt [3]3)

  • log r = log (2\times 3^{\frac{1}{3}})

  • log r = log 2+ log 3^{\frac{1}{3}}

  • log r = log 2+ \frac{1}{3}log 3

  • log r = 0.4600704139

  • Taking antilog on both sides, we find:

  • antilog(log r )= antilog(0.4600704139)

  • \implies r = 2.8844991406

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2 years ago
Name the slope and the y intercept for the equation y= 5x -7
NeTakaya

Answer:

The slope is 5x and the y-intercept is -7

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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I need help checking these
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Answer:

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