The extreme values of the function f(x) = x - 4sqrt(x) occur at the values of x for which f'(x) = 0
f'(x) = 1 - 2/sqrt(x) = 0
sqrt(x) - 2 = 0
sqrt(x) = 2
x = 4
To check for minimum or maximum,
f''(x) = 1/(sqrt(x))^3 = 1/(sqrt(4))^3 = 1/(2^3) = 1/8 => the point is a minimum.
Therefore, the minimum value = f(4) = 4 - 4sqrt(4) = 4 - 4(2) = 4 - 8 = -4 and occurs at x = 4.
Answer:
Is there a picture attached to this or how big the whole yard is?
Step-by-step explanation:
Answer:B or A is the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
there are six integers to win a lottery
case-1 Integer not exceeding 40
no of ways to choose 6 incorrect numbers


Case-2 no of ways to choose 6 incorrect numbers out of 48 integers


Case-3 no of ways to choose 6 incorrect numbers out of 56 integers


Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers


Answer:
let me make it its equation I have done this but if this will work have a good day