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3 years ago

Solve 41x-17y=99 17x-41y=75

Mathematics

2 answers:

Readme [11.4K]3 years ago

8 0

Answer:

X= 2 Y= -1

Step-by-step explanation:

Inga [223]3 years ago

7 0

I got no solution....

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navik [9.2K]

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-7x=56
Divide both sides by -7
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3 years ago

75 percent of the sutdents in a school went on a field trip. If 285 students went on the trip, how any students are in the schoo

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Answer:

380

Step-by-step explanation:

285 / x = 75 / 100

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Divide by 75 380

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Answer:

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Step-by-step explanation:

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2 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

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3 years ago

Read 2 more answers

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bagirrra123 [75]

What are you asking , if you tell me i will solve

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3 years ago

Read 2 more answers

Solve 41x-17y=99 17x-41y=75​

Solve 41x-17y=99 17x-41y=75