1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Finger [1]
3 years ago
14

A certain amount of gas is trapped in a nonrigid container at atmospheric pressure. If the container is cooled and the gas in th

e container remains at atmospheric pressure, what will happen? A. The number of moles of gas will decrease. B. The number of moles of gas will increase. C. The temperature of the gas will increase. D. The volume of the container will decrease. E. The volume of the container will increase.
Chemistry
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

D. The volume of the container will decrease.

Explanation:

  • We apply here, the general gas law of ideal gases:

<em>PV = nRT,</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas.

  • We are given that P is constant.

Also, n is constant as there is no added external gases.

T is decreased as the container is cooled.

So, the volume will change as the container is nonrigid.

<em>V α T.</em>

The volume is directly proportional to the temperature,

<em>Thus, as the container is cooled, the T will decrease, and the volume of the container will decrease.</em>

You might be interested in
Gold has a density of about 20.0g/mL this means that each milliliter has a mass of about __ grams.
qwelly [4]

Answer:

20.0 grams

Explanation:

If the density of gold is 20.0 g/mL, then we can multiply it by 1 mLto find the weight of 1 mL of gold.

20.0\frac{grams}{mL}*1mL=20.0 grams

8 0
3 years ago
Read 2 more answers
What do we call the type of chemical reaction that occurs in this step? Explain how the name of this type of reaction relates to
icang [17]
Figure it out yourself
6 0
2 years ago
Bacteria consume other organisms for food, making them heterotrophs. True or False?​
11111nata11111 [884]

Answer:

I would say true!

Explanation:

5 0
2 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0
2 years ago
When 5ml of HCl was added
777dan777 [17]

Answer:

A. There was still 140 ml of volume available for the reaction

Explanation:

According to Avogadro's law, we have that equal volumes of all gases  contains equal number of molecules

According to the ideal gas law, we have;

The pressure exerted by a gas, P = n·R·T/V

Where;

n = The number of moles

T = The temperature of the gas

R = The universal gas constant

V = The volume of the gas

Therefore, given that the volumes and number of moles of the removed air and added HCl are the same, the pressure and therefore, the volume available for the reaction will remain the same

There will still be the same volume available for the reaction.

5 0
2 years ago
Other questions:
  • What is not a trace gas found in our atmosphere oxygen,argon,carbon dioxide or neon
    12·1 answer
  • Which describes the volume of 1 mol of gas at standard temperature and pressure?
    12·1 answer
  • What is the percent yield if the actual yield is 25 g and 100 g should have formed?
    5·1 answer
  • The purpose of the salt bridge in an electrochemical cell is to ________. Question 10 options: provide oxygen to facilitate oxid
    12·1 answer
  • An engineer chooses to use bamboo as a building material because it grows
    15·2 answers
  • Is the final answer oxidation or reduction?
    14·1 answer
  • How many moles of NaOH must be dissolved in 1.00 L of water to make NaOH (aq) with a pH of 12.2?
    11·1 answer
  • Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. Enter your ans
    8·1 answer
  • A 25°C sample of gas has a volume of 5.0 L. What will it’s volume be if it is heated to 50.0°C?
    8·1 answer
  • PLEASE HELP ASAP WILL GIVE BRAINLIEST
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!