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iris [78.8K]
3 years ago
6

What is the molarity of 53.0 grams of HCl dissolved in 400.0 mL of water

Chemistry
1 answer:
Bond [772]3 years ago
8 0

Answer:

Molarity = 3.625 M

Explanation:

Given data:

Mass of HCl = 53.0 g

Volume of water = 400.0 mL (400/1000 = 0.4 L)

Molarity of solution = ?

Solution:

Number of moles of of HCl:

Number of moles = mass/ molar mass

Number of moles = 53 g/ 36.5 g/mol

Number of moles =1.45 mol

Molarity:

Molarity = number of moles of solute / volume of solution in L

Molarity =  1.45 mol / 0.4L

Molarity = 3.625 M

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What is the maximum concentration of Ag⁺ that can be added to a 0.00750 M solution of Na₂CO₃ before a precipitate will form? (Ks
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Answer:

\large \boxed{1.64\times 10^{-5}\text{ mol/L }}

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K_{sp} =\text{[Ag$^{+}$]$^{2}$[CO$_{3}^{2-}$]} = (2x)^{2}\times 0.00750 = 8.10 \times 10^{-12}\\0.0300x^{2} = 8.10 \times 10^{-12}\\x^{2} = 2.70 \times 10^{-10}\\x = \sqrt{2.70 \times 10^{-10}} = \mathbf{1.64\times 10^{5}} \textbf{ mol/L}\\\text{The maximum concentration of Ag$^{+}$ is $\large \boxed{\mathbf{1.64\times 10^{-5}}\textbf{ mol/L }}$}

 

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