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3 years ago

What is the molarity of 53.0 grams of HCl dissolved in 400.0 mL of water

Chemistry

1 answer:

Bond [772]3 years ago

8 0

Answer:

Molarity = 3.625 M

Explanation:

Given data:

Mass of HCl = 53.0 g

Volume of water = 400.0 mL (400/1000 = 0.4 L)

Molarity of solution = ?

Solution:

Number of moles of of HCl:

Number of moles = mass/ molar mass

Number of moles = 53 g/ 36.5 g/mol

Number of moles =1.45 mol

Molarity:

Molarity = number of moles of solute / volume of solution in L

Molarity = 1.45 mol / 0.4L

Molarity = 3.625 M

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2 years ago

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3 years ago

A sample of 4.0 L of nitrogen, at 1.2 atmospheres, is transferred to a 12 L container.

Zielflug [23.3K]

Answer:

The pressure will be 0.4 atm.

Explanation:

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P*V= k

If you initially have the gas at a volume V1 and press P1, when the conditions change to a volume V2 and pressure P2, the following is satisfied:

P1*V1= P2*V2

In this case:

P1= 1.2 atm
V1= 4 L
P2= ?
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Replacing:

1.2 atm* 4 L= P2* 12 L

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$P2=\frac{1.2 atm*4 L}{12 L}$

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