Answer:∠1 and ∠5
Step-by-step explanation:
(A) ∠3 and ∠6 forms the interior angles on the same side of the transversal. Thus, this option is incorrect.
(B) ∠1 and ∠4 forms the linear pair on the straight line a, thus this option is incorrect.
(C) ∠1 and ∠5 forms the corresponding angle pair, thus this option is correct.
(D) ∠6 and ∠7 forms the linear pair on the straight line a, thus this option is incorrect.
Answer:
value of x = 5
Step-by-step explanation:
Given:
∠L = ∠n
So,
ML = MN
So,
3x = x + 10
2x = 10
x = 5
value of x = 5
Answer:
1/8
Step-by-step explanation:
To simplify the expression √3/√8, we can first simplify the square root terms by finding the prime factorization of each number under the square root. The prime factorization of 3 is 3, and the prime factorization of 8 is 2 * 2 * 2.
We can then rewrite the square root terms as follows:
√3/√8 = √(3) / √(2 * 2 * 2)
Next, we can use the property of square roots that says that the square root of a number is equal to the square root of each of its prime factors. This means that we can rewrite the square root term as follows:
√(3) / √(2 * 2 * 2) = √(3) / √(2) / √(2) / √(2)
Since the square root of a number is the same as the number itself, we can simplify the expression further by removing the square root symbols from the prime numbers 2:
√(3) / √(2) / √(2) / √(2) = √(3) / 2 / 2 / 2
Finally, we can use the rules of division to simplify the expression even further:
√(3) / 2 / 2 / 2 = √(3) / (2 * 2 * 2)
Since any number divided by itself is equal to 1, we can simplify the expression one last time to get our final answer:
√(3) / (2 * 2 * 2) = 1/2 * 1/2 * 1/2 = 1/8
Therefore, the simplified form of the expression √3/√8 is 1/8.
Answer:
-12x - 4
Step-by-step explanation:
if you can please mark brainlyist
well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%246000%5C%5C%20r%3Drate%5Cto%204%5C%25%5Cto%20%5Cfrac%7B4%7D%7B100%7D%5Cdotfill%20%260.04%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B8%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B2%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D6000%5B1%2B%280.04%29%28%5Cfrac%7B2%7D%7B3%7D%29%5D%5Cimplies%20A%3D6000%5Cleft%28%20%5Cfrac%7B77%7D%7B75%7D%20%5Cright%29%5Cimplies%20A%3D6160)
well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.
what if she had left her money for 1 whole year, then
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%246000%5C%5C%20r%3Drate%5Cto%204%5C%25%5Cto%20%5Cfrac%7B4%7D%7B100%7D%5Cdotfill%20%260.04%5C%5C%20t%3Dyears%5Cdotfill%20%261%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D6000%5B1%2B%280.04%29%281%29%5D%5Cimplies%20A%3D6240)
so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?
