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Nadya [2.5K]
3 years ago
10

A moving walkway has a speed of 0.9 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of

1.1 m/s to the east. What is the man's velocity relative to the moving walkway?
Physics
1 answer:
Marina CMI [18]3 years ago
3 0
Since the man and the walkway has velocity (which is a vector) moving in the same direction, who would add the velocities together.

That means the relative velocity would be 2 m/s to the East

If you picture it in your mind, imagine walking down an escalator, you feel like you're moving faster than you really are.

In a different example, if the man was moving 0.9 m/s to the West, they are moving in opposite directions, which means you would subtract the 2 velocities.
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A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north
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Answer:

Magnitude of displacement = 2.07 km

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Let east represent positive x axis and north represent positive y axis.

A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north of west.

1.93 km due wast

           s ₁ = 1.93 i km

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           s₂ = -1.03 j km

3.84 km in a direction 52.8 ° north of west

           s₃ = -3.84 cos 52.8 i + 3.84 sin 52.8 j = -2.32 i + 3.06 j km

Total displacement

          s = s ₁+  s₂+ s₃ = 1.93 i - 1.03 j -2.32 i + 3.06 j = -0.39 i + 2.03 j

  Magnitude of displacement, =\sqrt{(-0.39)^2+2.03^2}=2.07km

Time taken = 1.771 hour

Magnitude of average velocity, =\frac{2.07}{1.771}=1.17km/hr

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