An object distance is
presented as s = 5f and we know that the mirror equation relates the image
distance to the object distance and the focal length.
The mirror equation is
1/f = 1/s + 1/s’ where the variable f stands for
the focal length of the mirror. Variable (s)
represents the distance between the mirror surface and the object and the
variable <span>(s’) represents the distance between the mirror surface and
the image. </span>
In addition, a concave mirror
will have a positive focal length (f) and a convex mirror will have a negative
focal length (f).
Now, we then have 1/f = 1/5f
+ 1/s’ which is s’ = 5f/4
Then we get the magnification
ratio that expresses the size or amount of magnification or reduction of the
object or image and to get the magnification, we use this equation: M= s’/s
M= 5f/4x5f
s’ = 1/4s
Therefore, the image height
is one fourth of the object height
Answer:
the color is green
- 602.93 nm ( orange color )
the observation is that there is a change of visible color
Explanation:
A) wavelength of visible light that is most strongly reflected from a point on a soap
refraction n = 1.33
wall thickness (t) = 290 nm
2nt = (2m +1 ) ∝/2 -----equation 1
note when m = 0
therefore ∝ = 4nt/ 1 = 4 * 1.33 * 290 = 1542.8nm we will discard this
when m = 1
equation 1 becomes
∝ = 4nt/3 =( 4 * 1.33 * 290) / 3 = 1542.8 / 3 = 514.27 ( wavelength )
the color is green
B) the wavelength when the wall thickness is 340 nm
∝ = 4nt / 2m +1
where m = 1
∝ = (4 * 1.33 * 340 ) / 3 = 1808.8 / 3 = 602.93 nm ( orange color )
the observation is that there is a change of visible color
Answer:
d = 68.18 m
Explanation:
Given that,
Initial velocity, u = 15 m/s
Finally it comes to stop, v = 0
Acceleration, a = -1.65 m/s²
Time, t = 2.5 s
We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :
So, the hayride will cover a distance of 68.18 m.
Answer:
Approximately 
, assuming friction between the vehicle and the ground is negligible.
Explanation:
Let 
denote the mass of the vehicle. Let 
denote the initial velocity of the vehicle. Let 
denote the spring constant (needs to be found.) Let 
denote the maximum displacement of the spring.
Convert velocity of the vehicle to standard units (meters per second):
.
Initial kinetic energy (
) of the vehicle:
.
When the vehicle is brought to a rest, the elastic potential energy (
) stored in the spring would be:
.
By the conservation of energy, if the friction between the vehicle and the ground is negligible, the initial 
of the vehicle should be equal to the 
of the vehicle. In other words:
.
Rearrange this equation to find an expression for , the spring constant:
.
Substitute in the given values 
, 
, and 
:
Answer: Polarization
Explanation: Polarization is the movement of electrons within a neutral object because of the electric field of a nearby charged object. It occurs without direct contact between the two objects.
For example, electrons in a metal plate can repelled by the negative charges in a plastic rod if the plastic rod is placed near the metal plate. The electrons move away from the plastic rod, thereby causing one side of the metal plate to be positively charged and the other side to become negatively charged.
