3 years ago

Is the amount of stretch of the springs proportional to the hanging mass? Explain briefly.

1 answer:

8 0

Answer:

When connected in parallel, the extension of both springs is the same, and the total elastic force will be equal to the sum of the forces in each spring: x=x1=x2,F=F1+F2. F=F1+F2,⇒kx=k1x1+k2x2=(k1+k2)x,⇒k=k1+k2.

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