What is the magnitude of vector K ?

Physics

1 answer:

vovangra [49]2 years ago

3 0

Answer:

Vector K = 8 m

Explanation:

The given figure shows a right angle triangle JKL. It is given that :

vector L = 10 m

vector J = 6 m

We have to find vector k. We can find it by using Pythagoras theorem. According to this theorem, the sum of squares of perpendicular and the base is equal to the square of the longest side.

$L^2=K^2+J^2$

$K^2=L^2-J^2$

$K^2=(100)^2-(6)^2$

K = 8 m

Hence, the magnitude of vector K is 8 m.

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