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kolbaska11 [484]
3 years ago
6

A​ student's course grade is based on one midterm that counts as 20​% of his final​ grade, one class project that counts as 20​%

of his final​ grade, a set of homework assignments that counts as 30​% of his final​ grade, and a final exam that counts as 30​% of his final grade. His midterm score is 64​, his project score is 80​, his homework score is 94​, and his final exam score is 77. What is his overall final​ score? What letter grade did he earn​ (A, B,​ C, D, or​ F)? Assume that a mean of 90 or above is an​ A, a mean of at least 80 but less than 90 is a​ B, and so on.
Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

His overall final​ score is 80.1.

His letter grade is a B.

Step-by-step explanation:

To find his grade, we multiply each grade by it's weight.

Grades and weights:

His midterm score is 64​. The midterm counts 20% = 0.2.

His project score is 80​. The project score counts 20% = 0.2.

His homework score is 94. The homework score counts 30%.

His final exam score is 77. It counts 30%.

What is his overall final​ score?

64*0.2 + 80*0.2 + 94*0.3 + 77*0.3 = 80.1

His overall final​ score is 80.1.

What letter grade did he earn​ (A, B,​ C, D, or​ F)?

At least 80 but less than 90 is a​ B. He scored 80.1, so his letter grade is a B.

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aleksandrvk [35]
11/4% = (11/4)/100 = 11/400 = 0.0275;
1/4 = 0.2500;
1/80 = 0.0125;
We observe that 0.0125 < 0.0275 and 0.0114 < 0.0275 and 0.2500 > 0.0275 and 0.12500 > 0.0275;

The answers are c. and d.
7 0
4 years ago
- Which of the following is the least?<br> A).27<br> B) 1/4<br> C) 3/8<br> D) 2/11<br> E) 11%
mezya [45]

Step-by-step explanation:

A) 0.27

B) 1/4 = 0.25

C) 3/8 = 0.375

D) 2/ 11 = 0.1818

E) 11% = 0.11

E is the correct answer

4 0
3 years ago
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Write a multiplication equation that shows the denominator of 3/4 and 1/2 are related
lutik1710 [3]
Hope that “3/4 x 2/4” is what you are looking for. You have to multiply the numerator and the denominator of the second term by 2.
6 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
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Refer to the diagram shown.
lions [1.4K]

Answer:

x=5

Step-by-step explanation:

According to SSS, RPS and RPQ should be similar angles. Since the length RP is the same, then RQP and RSP should be similar too. Therefore PRS and PRQ should be similar too. Since QP and RS are the same (7) then QR and PS needs to be same in length too.

2x+3 = 4x-7

10 = 2x

x=5

5 0
3 years ago
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