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Vaselesa [24]
3 years ago
12

Ariela is selling tickets to a play. Adult tickets cost $12.25 and children's tickets cost $8.75. The total amount of money she

collects from ticket sales is at least $90.
Let x represent the number of adult tickets sold. Let y represent the number of children's tickets sold.
 
Enter an inequality that represents the situation
Mathematics
1 answer:
schepotkina [342]3 years ago
5 0
The aduts paid 21.50
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Given g(x)=-3x-4 what is the x value when g(x)=2
stiks02 [169]

Answer:

x= -2

Step-by-step explanation:

2= -3(x)-4

6= -3x

-2= x

7 0
3 years ago
Urgent please help..
Vadim26 [7]

Answer:

Step-by-step explanation:

\text{The yellow area is half of the area of the square minus the area of the circle.}\\ \\ A_s=6^2=36\\ \\ A_c=\pi r^2=\pi 3^2=9\pi \\ \\ A_y=\frac{1}{2}(36-9\pi)\approx 3.9in^2

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3 years ago
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In a southern state, it was revealed that 5% of all automobiles in the state did not pass inspection. what is the probability th
Jobisdone [24]
Fortune Battle Royale
8 0
3 years ago
Please guys I am begging you to help me! This was due yesterday and I need help! SO please help!
jeka57 [31]

Answer:

  • Q3. 12 units
  • Q4. 6.33 units
  • Q5. 66.19°

Step-by-step explanation:

Q3

DE and DF are legs and EF is hypotenuse

  • DE = √EF² - DF²
  • DE = √13² - 5² = √169 - 25 = √ 144 = 12
  • DE = 12 units

Q4

PR is opposite side of angle Q and RQ is adjacent side

  • tan 54 = PR/RQ
  • tan 54 = PR / 4.6
  • PR = 4.6tan 54
  • PR = 6.33 units

Q5

As previous question, using tan as BC is opposite and AC is adjacent leg of angle A

  • tan A = 6.8/3
  • tan A = 2.266
  • A = arctan (2.266)
  • A = 66.19°
8 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
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