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mote1985 [20]
2 years ago
14

Mischka is an amateur astronomer. Using her telescope, she looks out past the Earth’s atmosphere and observes an object with a l

ong, bright, cloud-like tail behind it. What is Mischka observing?
an asteroid
a meteorite
a comet
a meteoroid
Physics
2 answers:
alexgriva [62]2 years ago
6 0

Answer: a comet

Explanation:  

A comet is composed of rock, ice dust and frozen gases. Comets generally reside in the outskirts of the solar system i.e. Kuiper belt and Oort cloud.

When comets enter the solar system, the frozen gases sublimate and form the atmosphere of the comet. It is known as coma. As the comet nears the Sun, the coma expands as more frozen gases sublimate and extends backwards due to solar wind. A huge tail composed of gases and dust is formed and can be observed through telescope from Earth. This must be observed by Mischka.

topjm [15]2 years ago
3 0
A comet is long and also bright, which has a blue-ish color to it. 

Best Regards, Mike
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A 19 kg solid disk of radius0.44 m is rotated about an
Vlad1618 [11]

Answer:

0.915 Nm

Explanation:

1 revolution = 2π rad

We can use the following equation of motion to find out the acceleration acting on the disk

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where \omega v = 2.5 rad/s is the final angular velocity of the disk, [tex]\omega_0 = 0 rad/s is the initial velocity of the can when it starts from rest, \Delta \theta is the angular distance traveled, \alpha is the angular acceleration of the disk, which we care looking for:

2.5^2 - 0 = 2*\alpha*2\pi

\alpha = \frac{2.5^2}{2*2\pi} \approx 0.5 rad/s^2

The moment of inertia of the solid disk is:

I = \frac{1}{2}mR^2 = \frac{1}{2}19*0.44^2 = 1.8392 kgm^2

where m is the mass and R is the radius of the disk

The net torque applied is

T = \alpha*I = 0.5 * 1.8392 = 0.915 Nm

8 0
2 years ago
suppose the ball has the smallest possible frequency that allows it to go all the way around the circle. what tension in the str
tatyana61 [14]

The complete question is missing, so i have attached the complete question.

Answer:

A) FBD is attached.

B) The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).

Explanation:

A) I've attached the image of the free body diagram.

B) The formula for the net force is given as;

F_net = mv²/r

We know that angular velocity;ω = v/r

Thus;

F_net = mω²r

Now, the minimum downward force is the weight and so;

mg = m(ω_min)²r

m will cancel out to give;

g = (ω_min)²r

(ω_min)² = g/r

ω_min = √(g/r)

The condition that must be satisfied is for ω_min = √(g/r)

C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).

5 0
2 years ago
Why are multiple images seen when two plane mirrors are placed at an angle​
Whitepunk [10]

Answer: Can I get a picture???

8 0
2 years ago
A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of
Fittoniya [83]

The acceleration of the air plane is 3.879 \mathrm{m} / \mathrm{s}^{2}

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

                         \text {Force }(F)=m \times \text { acceleration }(a)

The above equation can be written as below to find acceleration,

                        a=\frac{F}{m}

Now. Substitute the given values, we get,

                        a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}

3 0
2 years ago
An object has a velocity of 8 m/s and a kinetic energy of 480 j what is the mass of the object
dedylja [7]

We Know,

K.E. = 1/2 mv²

480 = 1/2 (m)(8)²

m = 960/64

m = 15 Kg

So, the mass of the object is 15 Kg


7 0
3 years ago
Read 2 more answers
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