Answer:
0.915 Nm
Explanation:
1 revolution = 2π rad
We can use the following equation of motion to find out the acceleration acting on the disk

where
= 0 rad/s is the initial velocity of the can when it starts from rest,
is the angular distance traveled,
is the angular acceleration of the disk, which we care looking for:


The moment of inertia of the solid disk is:

where m is the mass and R is the radius of the disk
The net torque applied is
The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Answer: Can I get a picture???
The acceleration of the air plane is 
<u>Explanation:</u>
Given:
The mass of the air plane = 1492.3 kg
Force of each four engine = 1447.5 N
So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N
The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

The above equation can be written as below to find acceleration,

Now. Substitute the given values, we get,

We Know,
K.E. = 1/2 mv²
480 = 1/2 (m)(8)²
m = 960/64
m = 15 Kg
So, the mass of the object is 15 Kg