Solution :
Given data is :
Density of the milk in the tank, 
Length of the tank, x = 9 m
Height of the tank, z = 3 m
Acceleration of the tank, 
Therefore, the pressure difference between the two points is given by :
Since the tank is completely filled with milk, the vertical acceleration is 
Therefore substituting, we get
Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.
Answer:
10N
Explanation:
Equation: ΣF = ma
Fapp = ma
Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)
Fapp = 10*kg*m/s^2
Fapp = 10N
Answer:
Push and pull both are forces , but the difference is in their direction at which it is applied . If the force applied in the direction of motion of the particle then we call it as push . If that force applied in the direction OPPOSITE to the motion of particle then it is termed as pull
Answer:
The answer to your question is the letter A) F = 9.23 x 10⁻⁷ N
Explanation:
Data
q₁ = -6.25 x 10⁻⁹ C
q₂ = -6.25 x 10⁻⁹ C
d = 0.617 m
k = 9 x 10⁹ Nm²/C²
F = ?
Formula
F = k q₁q₂ /r²
-Substitution
F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²
-Simplification
F = 3.512 x 10⁻⁷ / 0.381
-Result
F = 9.227 x 10⁻⁷ N ≈ 9.23 x 10⁻⁷ N
