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Rus_ich [418]
3 years ago
15

You have been asked to make a roller coaster more exciting. The owners want the speed at the bottom of the first hill doubled. H

ow much higher must the first hill be built?
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:

The height will be 4 times.

Explanation:

Given that,

The speed at the bottom of the hill doubled.

We need to calculate the height

Using conservation of energy

K.E_{t}+P.E_{t}=K.E_{b}+P.E_{b}

K.E_{b}=P.E_{t}

\dfrac{1}{2}mv^2=mgh

\dfrac{1}{2}m(4v^2)=mgh

Therefore,

P.E = mg(4h)

Here, m and g are constant

Hence, The height will be 4 times.

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3 years ago
Which court case provided for Judicial Review?
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6 0
3 years ago
A car is driving northwest at v mph across a sloping plain whose height, in feet above sea level, at a point n miles north and e
coldgirl [10]
Refer to the diagram shown.

Given:
h(n,e) = 1500 + 75n + 50e

Define 
\hat{r} = unit \, vector \, along \, \vec{v} \\ \hat{i} = unit \, vector \, east \\ \hat{j} = unit \, vector \, north \\ \nabla \equiv \hat{i}  \frac{\partial}{\partial e} + \hat{j}  \frac{\partial}{\partial n}

\hat{r} =  \frac{1}{ \sqrt{2} } (-\hat{i}+\hat{j} )

Then the rate of change of h with respect to the vector v is
\nabla h . \hat{r} = \frac{1}{\sqrt{2}}(50\hat{i} + 75\hat{j}).(-\hat{i}+\hat{j}) = \frac{1}{\sqrt{2}} (-50+75) =17.68

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It traveled 150 meters
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