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Ganezh [65]
3 years ago
8

Two loudspeakers are placed side by side and driven by the same source at 500 Hz. A listener is positioned in front of the two s

peakers and on the line separating them, thus creating a constructive interference at the listener's ear. If one of the speakers is gradually pushed toward the listener, how far must it be moved to repeat the condition of constructive interference at the listener's ear
Physics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

0.68 m

Explanation:

We know that the speed of sound in air is a product of frequency and wavelength. Taking speed of sound in air as 340 m/s

V=frequency*wavelength

Then wavelength is given by 350/500=0.68 m

Therefore, to repeat constructive interference at the listener's ear, a distance of 0.68 m is needed

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Which is the electric potential energy of a charged particle divided by its charge?Electric fieldelectric field lineelectric pot
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<h3><u>Answer;</u></h3>

electric potential

<h3><u>Explanation;</u></h3>

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2 years ago
A 81 kg person sits on a 3.8 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.2 cm in diameter
tankabanditka [31]

Answer:

1.9 MPa

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Mass of chair = 3.8 kg

Diameter of contact point = 1.2 cm = D

Radius of contact point = 1.2/2 = 0.6 cm

Total mass of chair and person = 81 + 3.8 = 84.8 kg = M

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Pressure

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Pressure exerted on the floor by each leg of the chair is 1.9 MPa

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