Answer:
F = 6666.7 N
Explanation:
Given that,
Mass of a chip, m = 0.1 mg
Initial speed, u = 0
Final speed,
Time of collision,
We know that,
Force, F = ma
Put all the values,
So, the required force is 6666.7 N.
Hen a gfci receptacle device is installed on a 20-ampere branch circuit (12 awg copper), what is the minimum volume allowance (i
n cubic inches) required for conductor fill for each conductor in the outlet box?
1 answer:
You might be interested in
Using the cosine rule (a^2 = b^2 + c^2 - 2bc cos A), we can work out the displacement:
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:
:
cos (C)=
= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:
cos (C)=
= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing