<span>buzzed, droned, jangled, reverberated.</span>
The troposphere contains 80% of the the atmosphere, including the majority of gases and water vapor.
Hope it helps!
In an uniformly accelerated motion, the velocity of the object follows the law:
where
is the initial velocity, a the acceleration and t the time.
In our problem, the robot starts from rest, so the initial speed is zero:
. The robot is in free fall, so the acceleraion is the gravitational acceleration
. therefore, after a time
, the velocity is
Answer:
the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
Explanation:
Given that;
speed of car V = 120 km/h = 33.3333 m/s
Reaction time of an alert driver = 0.8 sec
Reaction time of an alert driver = 3 sec
extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec
now, extra distance that car will travel in case of sleepy driver will be'
S_d = V × 2.2 sec
S_d = 33.3333 m/s × 2.2 sec
S_d = 73.3333 m
hence, number of car of additional car length n will be;
n = S_n / car length
n = 73.3333 m / 5m
n = 14.666 ≈ 15
Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
