Mass of block A above is 25-kg. Calculate the force of gravity on block A.

Monica [59]

<span>In real machines, efficiency is always less than 1 .</span>

6 0

3 years ago

The heater element of a 120 V toaster is a 5.4 m length of nichrome wire, whose diameter is 0.48 mm. The resistivity of nichrome

Ksenya-84 [330]

Answer:

The power drawn by the toaster is closest to:

(A) 370 W

Explanation:

First we calculate the resistance of the nichrome wire (R).

$R=\frac{pL}{A} =\frac{pL}{\pi r^{2} } \\$

Where radious (r), resistance coefficient (p), and Length (L)

$r=\frac{0.48}{2} 10^{-3} m\\\\L=5.4 m\\p=1.3*10^{-3}\varOmega \\\\\\Replacing:\\\\R=\frac{1.3(10)^{-6} *5.4}{\pi* 0.24^{2} (10)^{-6}} =38.7940$

After replace the value in the ohm law power formula to obtain the power consumed:

$P=\frac{V^2}{R} =\frac{120^2}{38.7940} =371.191 Watts$

7 0

3 years ago

WILL GIVE BRAINLYST A flower pot is thrown out of a window with a horizontal velocity of 8 m/s. If the window is 1.5 m off the g

stich3 [128]

-- Use the formula D=(1/2)·(g)·(t²) to calculate how long
it takes the flower pot to fall to the ground.

1.5 m = (1/2) · (9.8 m/s²) · (t²)

t² = (1.5 m) / (4.9 m/s²)

t = 0.554 second

-- Use the formula Distance = (speed)·(time) to calculate
how far the pot traveled horizontally in that amount of time.

Distance = (8 m/s) · (0.554 sec)

Distance horizontally = 4.43 meters

3 0

3 years ago

15 points! An atomic nucleus initially moving at 420 m/s emits an alpha particle in the direction of its velocity, and the remai

alexandr1967 [171]

The alpha particle is emitted at 4235 m/s

Explanation:

We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:

$p_i = p_f\\ Mu=m_1 v_1 + m_2 v_2 =$

where:

$M =222u$ is the mass of the original nucleus

$v=420 m/s$ is the initial velocity of the nucleus

$m_1 = 4 u$ is the mass of the alpha particle

$v_1$ is the final velocity of the alpha particle

$m_2 = 222u-4u = 218 u$ is the mass of the daughter nucleus

$v_2 = 350 m/s$ is the final velocity of the nucleus

Solving for $v_1$ , we find the final velocity of the alpha particle:

$v_1 = \frac{Mu-m_2 v_2}{m_1}=\frac{(222)(420)-(218)(350)}{4}=4235 m/s$

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

4 0

3 years ago

An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi

MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

$Ft*r=I*a$ -> $(Ft*r)/(a) = I$

Replacing we get that I is:

$I=(200N*0,33m)/(0,936rad/s^2)$

Then $I=70,513kgm^2$

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:

$I=(1/2)*(m*r^2)$

4 0

3 years ago