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worty [1.4K]
2 years ago
15

I need help on number 5

Chemistry
2 answers:
lilavasa [31]2 years ago
7 0
Itś C. Trust me........
ira [324]2 years ago
4 0
I agree, The answer is B. C Horizon. Hope this helps. :)
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A chemical reaction was carried out three times. The mass of the product was 8.93 g for the first trial, 8.94 g for the second t
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The three mass value measure are precise mass

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A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of heliu
Darina [25.2K]

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: V_{1} = 2.25 L,     n_{1} = 9.0 mol

V_{2} = 1.85 L,            n_{2} = ?

Formula used to calculate the moles of helium are as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

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A main group metal was studied and found to exhibit the following properties:
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