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3 years ago

The temperature of a substance can be described as:

Chemistry

1 answer:

inn [45]3 years ago

5 0

Answer:

Explanation:

the average kinetic energy of all the atoms or molecules of that substance.

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Order the density of the layers of the Earth from lowest density to highest

tatiyna

Answer:

the first is the inner core second is outer core third oceanic cruat fourth contenental crust fifth asthenosphere

3 0

3 years ago

2,3,5-trimethylhexane

dedylja [7]

2,3,5-trimethylhexane

C9H20

Molecular weight= 128.5g/mol

CH3-CH(CH3)-CH(CH3)-CH2-CH(CH3)-CH3

5 0

3 years ago

If 65 grams of sodium carbonate powder is reacted with excess sulfuric acid, then how many mL of gas over water are collected at

shtirl [24]

Answer:

Explanation:

7 0

3 years ago

An aerosol can with a temperature of 292 K and a pressure of 1.25 atm was left outside in the sun on a hot summer day. The press

garik1379 [7]

Answer:

310.69K

Explanation:

Given parameters:

Initial temperature T₁ = 292K

Initial pressure P₁ = 1.25atm

Final pressure P₂ = 1.33atm

Unknown:

Final temperature T₂ = ?

Solution

To find the unkown, we need to apply the combined gas law. From the combined gas law, it can be deduced that at constant volume, the pressure of a give mass or mole of gas varies directly with the absolute temperature.

Since the same aerosol can is heated, the volume is constant.

$\frac{P_{1} }{T_{1} }$ = $\frac{P_{2} }{T_{2} }$

Now, we have to make T₂ the subject of the formula:

T₂ = $\frac{P_{2} x T_{1} }{P_{1} }$

T₂ = $\frac{1.33 x 292 }{1.25 }$ = 310.69K

6 0

3 years ago

The empirical formula for trichloroisocyanuric acid, the active ingredient in many household bleaches is OCNCI. The molar mass o

TEA [102]

Answer:

These two are equivalent and valid:

$C_3Cl_3N_3O_3$

$Cl_3(CN)_3O_3$

Explanation:

The molecular superscripts for each atom in the molecular formula are determined by the number of times that the mass of the empirical formula is contained in the molar mass.

1. Determine the mass of the empirical formula:

$OCNCl$ :

Atomic masses:

O: 15.999g/mol
C: 12.011g/mol
N: 14.007g/mol
Cl: 35.453g/mol

Total mass:

15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol

2. Divide the molar mass by the mass of the empirical formula:

232.41g/mol / 77.470g/mol = 3

3. Multiply each superscript of the empirical formula by the previous quotient: 3

$O_3C_3N__3Cl_3$

Or:

$C_3Cl_3N_3O_3$

You might also write CN as a group:

$Cl_3(CN)_3O_3$

8 0

3 years ago