Help me find the IUPAC names please

What do scientists use to increase the surface area of a solute

marta [7]

use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.

6 0

3 years ago

Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)

Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

learn more about standard molar entropy:

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7 0

2 years ago

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b

Lelechka [254]

Answer:

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

Explanation:

A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol

Energy required to breakl sigle C-C bond:E

$E=\frac{348000 J/mol}{6.022\times 10^{23} mol^{-1}}=5.7788\times 10^{-19} J$

$E=\frac{h\times c}{\lambda}$

where,

E = energy of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of the radiation

Now put all the given values in the above formula, we get the energy of the photons.

$\lambda =\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{5.7788\times 10^{-19} J}$

$\lambda =3.4398\\times 10^{-7}m=343.98 nm$

$1 m = 10^{9} nm$

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

4 0

3 years ago

Be sure to answer all parts. find the molar solubility of bacro4 (ksp= 2.1 × 10−10) in (a) pure water × 10 m (b) 1.6 × 10−3 m na

Vlad [161]

A) in pure water :

by using ICE table:

According to the reaction equation:

BaCrO4(s) → Ba^2+(aq) + CrO4^2-(aq)

initial 0 0

change +X +X

Equ X X

when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X* X

∴X = √2.1 x 10*-10

∴X = 1.4 x 10^-5

∴ the solubility = X = 1.4 X 10^-5

B) In 1.6 x 10^-3 m Na2CrO4

by using ICE table:

According to the reaction equation:

BaCrO4(s) → Ba^2+(aq) + CrO4^2-(aq)

initial 0 0.0016

Change +X +X

Equ X X+0.0016

when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X*(X+0.0016) by solving for X

∴ X = 1.3 x 10^-7

∴ solubility =X = 1.3 x 10^-7

3 0

3 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

nirvana33 [79]

<u>Answer:</u> The volume of water required is 398 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

$0.16M=\frac{16g\times 1000}{251g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=398mL$

Hence, the volume of water required is 398 mL

7 0

3 years ago