In a parallel circuit, if bulb #2 were to blow out, bulb #1 would stay lit or go out?
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<h2>Answer:</h2><h2>The depth of barge float=3 cm</h2><h2>Explanation:</h2>
Length of rectangular barge=5.2 m
Width of rectangular barge=2.4m
Mass of crate=410 kg
Let h be the height of barge float
Volume of barge float=
Density of water=
Weight of water displaced by barge=Buoyant force=-Weight of horse
1 m=100 cm
cm
Hence, the depth of barge float=3 cm
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