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tatuchka [14]
3 years ago
6

Does a black hole have 2 sides that pull light together?

Physics
1 answer:
Ostrovityanka [42]3 years ago
8 0
Check this Light doesn't have mass or gravity right?
So if it doesn't have mass or gravity so light can only affect objects with mass
Does that make sense?
The black hole has gravity and remember light doesn't have gravity so does it affect the light?
To answer that yes, and since light doesn't have gravity it gets "pulled" into the black hole

I hope this helps you

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A skateboarder traveling with an initial velocity 9.0 meters per second,
meriva

Answer:

25m/s

Steps:

<em> First, The equation v= u + a * t shows us what we need to find, (the finale velocity). </em>

<em />

Second, we substitute the values given:

v= 9m/s + 4m/s2 * 4s

Last, We calculate the values:

Multiply 4m/s2 * 4s = 16m/s  

Add 9m/s + 16m/s

<u></u>

<u>Answer:  25m/s</u>

Hope this helps :)

4 0
3 years ago
a deer with a mass of 176 kg is running head-on towards you with a velocity of 19 m/s. you are going north. find the magnitude a
Igoryamba

Momentum = Mass × Velocity

According to this formula,

Momentum of deer = 176 × 19 = 3344 kg•m/s.

Since you are heading north and the deer is running towards you, the direction of the deer' s momentum is north as well.

6 0
3 years ago
A train travels due south at 25 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of e
olasank [31]

Answer:

Explanation:

Given

Train travels towards south with a velocity if v_t=25\ m/s

Rain makes an angle of \theta =66^{o}  with vertical

If an observer sees the drop fall perfectly vertical i.e. horizontal component of rain velocity is equal to train velocity

suppose v_r is the velocity of rain with respect to ground then

v_r\sin\theta =v_t

v_r\times \sin (66)=25

v_r=27.36\ m/s

Therefore velocity of rain drops is 27.36 m/s              

8 0
3 years ago
____________ is an out made when a base runner, forced to run because another teammate must run to the base being occupied, cann
maxonik [38]
If I knew the answer I would help but I don’t know sorry
5 0
2 years ago
Estimate the number of atoms in 1 cm^3 of a solid
dexar [7]
Avogadro's number: 6.02 x 10^23 atoms is present in 1mol of a solid (i.e. 22, 400 cm3)

Hence, in 1 cm3, 6.02 x 10^23 /22400 atoms is present = 2 x 10 ^ 19 atoms.
7 0
3 years ago
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