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2 years ago

If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?

Physics

1 answer:

Anton [14]2 years ago

7 0

Answer:

$E=1.62\times 10^{14}\ J$

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

$E=mc^2$

Where

c is the speed of light

So,

$E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J$

So, the energy obtained is $1.62\times 10^{14}\ J$ .

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What type of metal are conducting wires most often made of?<br><br> #16

docker41 [41]

Answer:

here

Explanation:

Copper is commonly used as an effective conductor in household appliances and in electrical equipment in general. Because of its low cost, most wires are copper-plated. You will often find electromagnet cores normally wrapped with copper wire

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1 year ago

calculate the period of a wave whose frequency is 5 Hertz and whose wavelength is one centimeter give your answer in a decimal f

olga2289 [7]

The period of the wave is the reciprocal of its frequency.

1 / (5 per second) = 0.2 second .

The wavelength is irrelevant to the period. But since you
gave it to us, we can also calculate the speed of the wave.

Wave speed = (frequency) x (wavelength)

= (5 per second) x (1cm) = 5 cm per second

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3 years ago

A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the

Bond [772]

Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

$qvB = m\frac{v^2}{r}$

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

$T=\frac{2\pi r}{v}$

Re-arranging for r

$r=\frac{Tv}{2\pi}$

And substituting into the previous equation

$qvB = m \frac{Tv^3}{2\pi}$

Solving for T,

$T=\frac{2\pi q B}{m v^2}$

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

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3 years ago

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agasfer [191]

Lighting flows around the outside of a truck, and the majority of the current flows from the cars metal cage into the ground below. It's not very safe to be in a car or truck during bad weather.

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3 years ago

A 40 kg boy on a skateboard throws a 2 kg ball at 20 m/s to the left. How fast did the boy move to the right on his skateboard?

sergey [27]

According to my examination I have confirmed that I do NOT repeat do NOT know this .

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2 years ago