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2 years ago

If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?

Physics

1 answer:

Anton [14]2 years ago

7 0

Answer:

$E=1.62\times 10^{14}\ J$

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

$E=mc^2$

Where

c is the speed of light

So,

$E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J$

So, the energy obtained is $1.62\times 10^{14}\ J$ .

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Answer:

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Explanation:

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L = Length of wire = 55 cm

N = Number of turns = 4000

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Answer:

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3 years ago

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A particle with a positive charge q is moving in the positive x direction with velocity of magnitude v0. If there were an electr

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Answer:

First, let's define the coordinate axes: positive x direction is to the right, positive y direction is to upwards, and z direction is out-of-the plane (towards you).

If the particle is moving with velocity $v_0$ in the presence of an external E-field, than according to the below formula E-field pushes the positive charge in the direction of the field, which is upward.

$F = Eq$ .

If the velocity of the particle is unchanged, this means that the particle does not have an acceleration, so net force applied to the particle is zero.

We know that the force caused by the E-field is upwards, so an equal amount of another force is directed downwards. This second force is caused by magnetic field. $|F_B| = qvB$

$F_{net} = 0\\F_{net} = F_E - F_B\\0 = qE_0 - qvB\\qE_0 = qvB\\B = \frac{E_0}{v}$

This is the magnitude of the magnetic field.

For the direction of the magnetic field we can use right-hand rule with the following equation:

$F_B = q(v \times B)$

Here, $v$ is in the x-direction. $F_B$ is in the (-y)-direction.

According to the right-hand rule, B-field should be in the z-direction (out-of-the plane, towards you.)

Explanation:

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