WELP ITS MATH SEE BELOW

Perry traveled at an average speed of 55 miles per hour for 3.5 hours and then traveled at an average speed of 60 miles per hour

Alex

Answer:

342.5

Step-by-step explanation:

Take 55 and multiply it by 3.5

Then multiply 60 by 2.5

Then add those two numbers that you come up with and add them together.

7 0

3 years ago

(Will make brainliest if correct)

Mice21 [21]

Since 4 peaches x 2 =8, you would would only be able to buy 6 mangos since $1.25 x 6 mangos =$7.5 so it would be $7.5+$8=$15.5 and 6 mangos+4 peaches=10 in total. And he would also save $5.00! :)

Please mark brainliest!

Hope it helps!

4 0

3 years ago

Evaluate the expression for the given value of x. <br><br> −7x + 5 for x = −7

notsponge [240]

Answer:

X is 49 +5 that is 54

.........

5 0

3 years ago

Ms.Friedman and Mrs.Elliot both teach sixth grade math. They share a storage closet. What is the total area of both rooms and th

Citrus2011 [14]

Answer:
Total area of both rooms and the storage = 2844 ft^2

Explanation:
Total area would initially be the summation of the area of Ms. Friedman's room and storage added to Mrs. Elliot's room and storage.
However, we are given that the storage is shared.
So now, the total area would be equal to Ms. Friedman's room and storage + Mrs. Elliot's room and storage - area of closet

Now, we can notice that:
Ms. Friedman's room and storage = Mrs. Elliot's room and storage

Therefore:
Total area = 2*Ms. Friedman's room and storage - area of storage

1- getting area of Ms. Friedman's room and storage:
length = 36 ft
width = 40 ft
area of Ms. Friedman's room and storage = length * width
area of Ms. Friedman's room and storage = 36 * 40
area of Ms. Friedman's room and storage = 1440 ft^2

2- getting area of closet:
length = 36 - 30 = 6 ft
width = 40 - 34 = 6 ft
area of closet = length * width
area of closet = 6 * 6 = 36 ft^2

3- total area of both rooms and the storage:
Total area = 2*Ms. Friedman's room and storage - area of storage
Total area = 2*1440 - 36
Total area = 2844 ft^2

Hope this helps :)

8 0

3 years ago

A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of

ELEN [110]

Answer:

$\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}$

$80.341 \leq \sigma^2 \leq 128.495$

Now we just take square root on both sides of the interval and we got:

$8.963 \leq \sigma \leq 11.336$

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

$\bar x$ represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

$\chi^2_{\alpha/2}=123.225$

$\chi^2_{1- \alpha/2}=77.046$

And replacing into the formula for the interval we got:

$\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}$

$80.341 \leq \sigma^2 \leq 128.495$

Now we just take square root on both sides of the interval and we got:

$8.963 \leq \sigma \leq 11.336$

5 0

3 years ago