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3 years ago

How can you lower the pH of the vinegar?

Chemistry

2 answers:

olchik [2.2K]3 years ago

5 0

D. Add water to the vinegar

stiks02 [169]3 years ago

5 0

Answer:

D. Add water to the vinegar to dilute it.

Explanation:

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PLEASE HELP I NEED THIS ANSWERED IN 10 MINS PLEASE

elena-14-01-66 [18.8K]

We are given the equation to use which is:
ΔG = ΔH - TΔS

We are also given that:
ΔG = 173.3 kJ
T = 303 degrees kelvin
ΔH = 180.7 kJ

Substitute with these givens in the above equation to get ΔS as follows:
ΔG = ΔH - TΔS
173.3 = 180.7 - 303ΔS
303ΔS = 180.7 - 173.3
303ΔS = 7.4
ΔS = 7.4 / 303 = 0.02442 kJ/K which is equivalent to 24.42 J/k

Based on the above calculations, the correct choice is:
D. 24.42 J/K

4 0

3 years ago

Nvm i have to answer lol

DIA [1.3K]

Answer:

i will do a joke... hmmm...

Explanation:

why did the nurse need a red pen?

To draw out blood. lol

5 0

2 years ago

Read 2 more answers

Consider a sample of a hydrocarbon (a compound consisting of only carbon and hydrogen) at 0.959 atm and 298 K. Upon combusting t

Masja [62]

Answer:

Molecular formula of hydrocarbon is: C₂H₆

Explanation:

The combusting of the hydrocarbon:

CxHy + O₂ → CO₂ + H₂O

Using gas law to obtain molar mass of the gas mixture (CO₂ + H₂O):

P/RT = n/V

Where:

P is pressure (1,208 atm)

R is gas constant (0,082 atmL/molK)

T is temperature (375 K)

n/V = 0,0393 mol/L

1,1128 g/L ÷ 0,0393 mol/L = 28,32 g/mol

Thus, average molecular weight is:

28,32 g/mol = 44,01 g/mol X + 18,02 g/mol Y

1 = X + Y

Where X is CO₂ molar percentage and Y is H₂O molar percentage.

Solving:

X = 0,397

Y = 0,603

39,7% H₂O

60,3% CO₂

With this proportion you can obtain ratio CO₂:H₂O thus:

60,3/39,7 = 1,52 So, 2 CO₂: 3H₂O

The moles of the hydrocarbon are:

PV/RT = n

P (0,959 atm)

V ( 1/5 of final volume)

T (298K)

n = 7,85x10⁻³ mol

The moles of CO₂ are:

0,0393 mol × 2 mol CO₂/ 5 mol total =0,01572.

Ratio of CO₂:CxHY =

0,01572 : 7,85x10⁻³ 2 CO₂: 1 CxHY

Doing:

1 CxHy + O₂ → 2 CO₂ + 3 H₂O

By mass balance:

1 C₂H₆ + 7/2 O₂ → 2 CO₂ + 3 H₂O

Thus, molecular formula of hydrocarbon is: <em>C₂H₆ </em>

I hope it helps!

7 0

3 years ago

If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?

Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

$^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}$

Where:

A: is the mass number

Z: is the number of protons

β⁻: is a beta particle = electron

$\bar{\nu_{e}}$ : is an antineutrino

The neutral atom has 88 electrons, so:

$e^{-} = 88 = Z$

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

$^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}$

$^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}$

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!

8 0

2 years ago

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water

bearhunter [10]

Mass of Oxygen required : 24 grams

<h3>Further explanation</h3>

Given

3 moles of H

1.5 moles of O

3 moles of H₂O

Required

Mass of O

Solution

Reaction

2H₂ + O₂ ⇒ 2H₂O

Mass of Oxygen for 1.5 moles of O :

= mol x Ar O

= 1.5 moles x 16 g/mol

= 24 grams

7 0

2 years ago