Which of the following is a nonpolar molecule?
1 answer:
<u>Answer:</u> The correct option is A) a nitrogen molecule.
<u>Explanation:</u>
Polar covalent molecules are defined as chemical compounds in which the difference in electronegativity between the atoms is not equal to 0. These molecules are formed by heteronuclear molecules.
Heteronuclear molecules are defined as the molecules which are formed by the combination of more than one type of atom having a different nucleus.
Non-polar covalent molecules are defined as chemical compounds in which the difference in electronegativity between the atoms is equal to 0. These molecules are formed by homonuclear molecules.
Homonuclear molecules are defined as the molecules which are formed by the combination of one type of atom having the same nucleus.
From the given options:
- A) A nitrogen molecule
It is a homonuclear molecule formed by the combination of 2 nitrogen atoms
- B) A nitrogen monoxide molecule
It is a heteronuclear molecule formed by the combination of 1 nitrogen and 1 oxygen atoms
- C) A linear nitrogen oxide molecule
with nitrogen in the center
It is a heteronuclear molecule formed by the combination of 2 nitrogen and 1 oxygen atom and has some dipole moment. Thus, is considered a polar molecule
- D) A bent nitrogen dioxide molecule
with nitrogen in the center
It is a heteronuclear molecule formed by the combination of 1 nitrogen and 2 oxygen atoms and has some dipole moment. Thus, is considered a polar molecule
Hence, the correct option is A) a nitrogen molecule.
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Answer:
The heat absorbed by the sample of water is 3,294.9 J
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous). Its mathematical expression is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
- Q=?
- m= 45 g
- c= 4.184
- ΔT= Tfinal - Tinitial= 38.5 C - 21 C= 17.5 C
Replacing:
Q= 4.184 * 45 g* 17.5 C
Solving:
Q=3,294.9 J
<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>
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