Answer:
Explanation:
SO in order to calculate the specific latent heat of fusion, you need to remember the formula:
Where representes the specific latent heart of fusion.
represents the heat energy added, usually represented in kJ
represents the mass of the object, in kg.
Now that we have our formula we just have to put our values into the formula:
SO our answer would be
<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of NaBr = 11.1 g
Molar mass of NaBr = 103 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of 1-butanol and NaBr is:
By Stoichiometry of the reaction
1 mole of NaBr produces 1 mole of 1-bromobutane
So, 0.108 moles of NaBr will produce = moles of 1-bromobutane
Molar mass of 1-bromobutane = 137 g/mol
Moles of 1-bromobutane = 0.108 moles
Putting values in equation 1, we get:
Experimental yield of 1-bromobutane = 7.2 g
Theoretical yield of 1-bromobutane = 14.80 g
Putting values in above equation, we get:
Hence, the percent yield of the 1-bromobutane is 48.65 %