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Colt1911 [192]
3 years ago
12

Based on the information in the graph, which statement best applies to a gas?

Chemistry
2 answers:
Genrish500 [490]3 years ago
5 0
I think the right answer would be its particles have the most astounding normal dynamic vitality. Gas particles have a tendency to have the most astounding active vitality among the conditions of matter. They move in arbitrary movement. Trust this answers the question. Have a decent day.
MatroZZZ [7]3 years ago
4 0

Its particles have the highest average kinetic energy.

hope this helps!

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1 calorie is equal to ______ Joules.
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1 calorie is equal to 4.184 Joules.
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How many moles of water are needed to react with 2.2 moles of li2o? given: li2o + h2o â 2 lioh?
Debora [2.8K]
Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.

Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
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3 years ago
2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Slav-nsk [51]

Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

0.589 moles of AgCl × (143.32g / mol) =<em> 84.4g of AgCl</em>

3 0
4 years ago
What is not a factor in soil type?
SpyIntel [72]
The answer to this questions is letterB
7 0
3 years ago
In chemistry what is nickle (II) nitrate solution mixed with a sodium hydroxide solution
AlladinOne [14]

Answer:

I hope this will help you and Please mark me as Brilliant

Explanation:

Approximately 2 mL of Solution A (on the left) is added to a sample of Solution B (on the right) with a dropping pipet. If a precipitate forms, the resulting precipitate is suspended in the mixture. The mixture is then stirred with a glass stirring rod and the precipitate is allowed to settle for about a minute.

Solution A: 0.5 M sodium hydroxide, colorless

Solution B: 0.2 M nickel(II) nitrate, green

Precipitate: light green

Ni(NO3)2(aq) + 2 NaOH(aq) —> Ni(OH)2(s) + 2 NaNO3(aq)

Credits: 

Design

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

John W. Moore University of Wisconsin - Madison, Madison, WI 53706

Video

Jerrold J. Jacobsen University of Wisconsin - Madison, Madison, WI 53706

Text

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

6 0
3 years ago
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