Answer:
grams H₂O produced = 8.7 grams
Explanation:
Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)
7g 18g ?g
Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water
Moles Reactants
moles C₂H₆ = 7g/30g/mol = 0.233mol
moles O₂ = 18g/32g/mol = 0.563mol
Limiting Reactant => (Test for Limiting Reactant) Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.
moles C₂H₆/2 = 0.233/2 = 0.12
moles O₂/7 = 0.08
<u><em>Limiting Reactant is O₂</em></u>
Moles and Grams of H₂O:
Use Limiting Reactant moles (not division value) to calculate moles of H₂O.
moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield
grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O
Answer:
0.5 mole
Explanation:
C=12u
O=16u
1 mole carbon dioxide=44 grams
so 22grams = 0.5 mole
Answer:
O A. A metal higher on the activity series list will replace one that is
lower.
1. Density=mass/volume=2kg/6m=0.33kg/m (convert to proper units)
2. Density=mass/volume=0.6kg/3L=0.2kg/L (convert to proper units)
3. Density=mass/volume= 129g / 30 cm (convert to proper units)
V=length*width*height=2*3*5 = 30
4. Volume (units) = cm^3 because, like in problem 3, Volume=width(cm)*length(cm)*height(cm)
However, when you pour liquid into a cylinder (so the volume would be the liquid), you measure it in mL.
5. Volume with rock - initial volume (without the rock) = Volume of rock
18.2-12.7= 5.5
The correct answer is this: THE NUCLEUS OF AN ATOM SPLITS INTO FRAGMENTS, RELEASING A LARGE AMOUNT OF ENERGY.
Nuclear fission is the process in which the nucleus of a radioactive element split into two different nucleic of smaller sizes of different elements with a large release of energy. Nuclear fission process is usually used to provide energy for electricity generation.
