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belka [17]
2 years ago
13

Think about something very important to you that you would like to accomplish 10 years from now. Write a short-term, medium-term

, and long-term goal that will help you accomplish your future plans.
Chemistry
1 answer:
Vinil7 [7]2 years ago
5 0

Answer:

Goal: to propose a strategy to mitigate carcinogenic dyes present in wastewater.

Explanation:

Hello,

Short-term: Based on my interest about the treatment of carcinogenic effluents in the dyes industry, I'm planning to develop a research about how fast microorganisms could decompose such dyes in order to provide pure water-composed outlet streams. For now, I can suggest that they could work as long as they grow in a simulated dye-rich environment.

Medium-term: In such a way, the subsequent plan is to set up the reaction scheme and the reactor design stage for this bioprocess by running several test in order to collect the experimental data to back up the proposed mathematical model.

Long-term: Finally, the start-up of the whole process starting by the inlets and operation conditions, continuing by the innermost sub processes to decompose the dye and the subsequent adaptation of the outlet streams to produce drinkable water, will be carried out in order to help the environment and living things that are highly affected by those dyes.

Best regards.

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arsen [322]

We know that Weighted atomic mass of Element is Calculated based upon their existence of isotopes and the Relative abundance of these isotopes.

Given that the Element X is Composed of :

Isotope                       Relative abundance                   Atomic Mass

⁵⁵X                                        70%                                               55

⁵⁶X                                        20%                                               56

⁵⁷X                                        10%                                                57

Weighted Atomic Mass of Element X :

= (0.70)(55) + (0.20)(56) + (0.10)(57)

= 38.50 + 11.2 + 5.70

= 55.4

So, the Weighted Atomic Mass of Element X is 55.4

6 0
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I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
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