Question

3Al + 3NH4ClO4 → Al2O3 + AlCl3 + 3NO + 6H2O How many moles of AlCl3 are produced?

Answer 1

Answer: 1 mol of $AlCl_3$ will be produced from this reaction.

Explanation: Reaction follows,

$3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc$

As seen from the balanced chemical equation above, we get

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$, 1 mole of $Al_2O_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$, 1 mole of $AlCl_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$, 3 moles of $NO$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$, 6 moles of $H_2O$ is formed.

Answer 2

The answer is 746 moles of water are produced from 373 moles of Al.