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alexdok [17]
3 years ago
9

3Al + 3NH4ClO4 → Al2O3 + AlCl3 + 3NO + 6H2O How many moles of AlCl3 are produced?

Chemistry
2 answers:
zhuklara [117]3 years ago
7 0

Answer: 1 mol of AlCl_3 will be produced from this reaction.

Explanation: Reaction follows,

3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc

As seen from the balanced chemical equation above, we get

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 1 mole of Al_2O_3 is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 1 mole of AlCl_3 is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 3 moles of NO is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 6 moles of H_2O is formed.

Kay [80]3 years ago
7 0

The answer is 746 moles of water are produced from 373 moles of Al.

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Non-living factors in an ecosystem are ______.
mash [69]

Answer:

B. abiotic

Explanation:

in biology and ecology, abiotic components or abiotic factors are non living chemical and physical parts of the environment that affect living organisms and the functioning of ecosystems.

5 0
2 years ago
If HCl is a 0.05 M solution and 50 mL is used to titrate the NaOH, what is the molarity of NaOH if the flask contains 100 mL?
Liono4ka [1.6K]

Answer:

Molarity of NaOH = 0.025 M

Explanation:

Given data:

Molarity of  HCl = C₁ = 0.05 M

Volume of HCl = V₁= 50 mL

Molarity of NaOH = C₂=?

Volume of NaOH =V₂= 100 mL

Solution:

Formula:

C₁V₁  = C₂V₂

C₁ = Molarity of  HCl

V₁  = Volume of HCl

C₂ = Molarity of NaOH

V₂ = Volume of NaOH

Now we will put the values:

C₁V₁  = C₂V₂

0.05 M × 50 mL = C₂ × 100 mL

2.5 M.mL =C₂ × 100 mL

C₂  = 2.5 M.mL /100 mL

C₂  = 0.025 M

7 0
3 years ago
What are the benefits and limitations to relative dating rock layer?
vlabodo [156]
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4 0
3 years ago
What volume will 0.875 moles of Kr occupy at STP
umka21 [38]

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6 0
3 years ago
A glass holds 6 ounces of 60-proof rum (30 alcohol). how much fruit juice must be added to the rum so that the mixture is dilute
Elenna [48]

We need an equation that will relate the concentrated mixture and the diluted one. To solve this we use the equation, 

M1 V1 = M2 V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1V1 = M2V2

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V2 = 9 oz 


The volume of the diluted mixture would be 9 oz. Therefore, you will need to add 9 oz - 6 oz = 3 oz of fruit juice to dilute the 30 percent alcohol to 20 percent alcohol.

7 0
3 years ago
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