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inysia [295]
3 years ago
7

4. A compact disc has a diameter of 11.8 cm. What is the surface area of the disc in square centimeters? In square meters? [Area

of a circle = (π)(radius) 2 ]
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
8 0
<span>The surface area is 109.3 square centimeters or 0.01093 square meters. The area formula requires that we use the radius of the disc. We can find the radius by diving the diameter by 2, so radius = 11.8/2 or 5.9 cm. We can use 3.14 as an approximation for π. The surface area is 3.14 * (5.9*5.9). Since the diameter is given in cm, the surface area units are in square centimeters. To convert to meters, divide any measurement in centimeters by 100, but we need to convert to "square" meters, so we need to divide our square centimeters by 100 * 100, or by 10,000. Dividing 109.3 by 10,000 results in 0.01093 square "meters".</span>
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Hello! The correct answer is, B. are in motion outside the nucleus.


I hope this helped!

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We have a sample of water vapor which cools from 150 °C to 125 °C. What happens to the motion of the molecules during this time
pentagon [3]

The motion of the molecules decreases.

<u>Explanation</u>:

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5 0
3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2
Setler79 [48]

Answer:

a) volume of ammonium iodide required =349 mL

b) the moles of lead iodide formed = 0.0436 mol

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The reaction is:

Pb(NO_{3})_{2}+2NH_{4}I -->PbI_{2}+2NH_{4}NO_{3}

It shows that one mole of lead nitrate will react with two moles of ammonium iodide to give one mole of lead iodide.

Let us calculate the moles of lead nitrate taken in the solution.

Moles=molarityX volume (L)

Moles of lead nitrate = 0.360 X 0.121 =0.0436 mol

the moles of ammonium iodide required = 2 X0.0436 = 0.0872 mol

The volume of ammonium iodide required will be:

volume=\frac{moles}{molarity}=\frac{0.0872}{0.250}=0.349L=349mL

the moles of lead iodide formed = moles of lead nitrate taken = 0.0436 mol

7 0
3 years ago
The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
enot [183]

Answer: C=\frac{\pi}{R\times T}

Explanation:-

Osmotic pressure is a colligative property which depends on the amount of solute added.

\pi=CRT

\pi = osmotic pressure = 5.1 atm

C= concentration in Molarity

R= solution constant = 0.0821 Latm/Kmol

T= temperature = 312 K

C=\frac{\pi}{R\times T}

C=\frac{5.1atm}{0.0821Latm/Kmol\times 312K}=0.2mol/L

Thus the equation for calculating the molarity of this solution is C=\frac{\pi}{R\times T}

4 0
3 years ago
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