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3 years ago

There are 55.0 g of neon gas in a 3.0 L cylinder, the pressure is 4.5 atm what is the temp of the gas

Chemistry

1 answer:

marshall27 [118]3 years ago

4 0

Answer:

60.9 Kelvin

Explanation: First, write out everything that you know. You are tring to find the temperature, so the temperature will be represented by x.

Pressure (P)= 4.5 atm

Volume (V)= 3L

Number of Moles (n)= ?

Gas Consant (R)= 0.0821, if the pressure is in atm, that means r is 0.0821

Temperature (T)= x

We don't have all the information we need to plug the values into the equation. We still need to know how many moles 55.0 grans of neon is.

Ne in Grams= 55

Atomic Mass of Ne= 20.1797

55/20.1797= 2.7

moles= 2.7

Now that we have all the information we need, plug everying into the equation. In case you don't know, the Ideal Gas Law Equation is PV= nRT.

(4.5)(3) = (2.7)(0.821)x

x= 60.9

Now you have your temperature! It is 60.9 in Kelvin.

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Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)

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Mass of $Ag_3PO_4$ =

Moles of $Ag_3PO_4$ × Molar Mass of $Ag_3PO_4$

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of $Ag_3PO_4$ is produced.

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