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3 years ago

¿Cuáles son las formas alotrópicas del carbono (como se encuentra en la naturaleza)?

1 answer:

3 0

Answer: El carbono, que en estado sólido, puede adoptar muchas formas alotrópicas, siendo las más comunes el diamante (red tridimensional) y el grafito (láminas), aunque también puede formar nanoestructuras en forma de balón de fútbol (fullerenos) o tubos diminutos (nanotubos de carbono), entre otras posibilidades.

Explanation:

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The particles in the most solids are arranged in a regular pattern.

borishaifa [10]

True because solids are colder so the particles are in a fixed pattern that join them into a regular pattern

5 0

3 years ago

What is the lewis structure for CH2ClCOO-

FrozenT [24]

Answer: The Lewis structure of Chloroacetate can be found at the attachment below.

Explanation:

CH2ClCOO- The chemical compound is called Chloroacetate.

Reference link for the Chloroacetate structure.

https://www.google.com/search?q=lewis+structure+for+CH2ClCOO-&prmd=ivn&sxsrf=ALeKk03mQcLiY-q5pEriMR0_26ZTXLjmJg:1589680325594&source=lnms&tbm=isch&sa=X&ved=2ahUKEwjfxPPY5LnpAhVloXEKHeAwD-wQ_AUoAXoECA4QAQ&cshid=1589680746615&biw=360&bih=559&dpr=3#

5 0

3 years ago

Why does iron not fit the pattern in column 7

son4ous [18]

Iron doesn't fit because it doesn't have enough atoms or protons in its nucleus so there for it belongs in column 2. <span />

3 0

4 years ago

What coefficient of h+ balances the atoms in this half-reaction h+ + mno2 → mn2+ + h2o?

kvv77 [185]

The answer is 4 im pretty sure

7 0

3 years ago

Read 2 more answers

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0

3 years ago