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mihalych1998 [28]
4 years ago
10

Test tubes are used mostly for _____. A. storing experimental samples B. making precise measurements of liquids C. containing ex

tra chemicals left over from an experiment D. holding substances so they can be viewed using a microscope
Chemistry
1 answer:
Annette [7]4 years ago
8 0

Answer: A) Storing experimental samples

Explanation:

It is a common piece of laboratory glassware that can be made of glass or plastic and is opened at the top and closed at the bottom.

It cannot be used for measurements because there is no graduation indicating the volume.

Althought it can contain extra chemicals left over from an experiment, it is not the main proposal of the glassware that is to store samples.

It cannot be used in a microscope and the object for that is a microscope slide.

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Boron trifluoride gas is collected at in an evacuated flask with a measured volume of . When all the gas has been collected, the
Vaselesa [24]

Answer:

0.683 mol

46.3 g

Explanation:

There is some info missing. I think this is the original question.

<em>Boron trifluoride gas is collected at 21.0 °C in an evacuated flask with a measured volume of 50.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.330 atm. Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to 3 significant digits.</em>

<em />

Step 1: Convert the temperature to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 21.0°C + 273.15

K = 294.2 K

Step 2: Calculate the moles of boron trifluoride gas

We will use the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T}  = \frac{0.330atm \times 50.0L}{\frac{0.0821atm.L}{mol.K}  \times 294.2K} = 0.683 mol

Step 3: Calculate the mass of boron trifluoride gas

The molar mass of BF₃ is 67.81 g/mol.

0.683 mol \times \frac{67.81g}{mol} = 46.3 g

8 0
3 years ago
How much (in mL) 12.1 M solution of hydrochloric acid would be required to make 500 mL of a 2.5 M solution
victus00 [196]

Answer:

Volume of the concentrated solution, which is needed is 103.30 mL

Explanation:

Let's apply the formula for dilutions to solve the problem

Conc. Molarity . Conc. volume = Dil. Molarity . Dil volume

12.1 M . Conc. volume = 2.5 M . 500 mL

Conc. volume = (2.5 M . 500 mL) / 12.1M

Conc. volume = 103.30 mL

6 0
4 years ago
The molality of a solution that is made by dissolving a certain mass of benzene in 20.6g of carbon tetrachloride is 0.529m. How
antiseptic1488 [7]
Molality of solution = 0.529 m

mass solvent in kg = 20.6 g => 20.6 / 1000 => 0.0206 kg

number of moles = molality x mass solvent

= 0.529 x 0.0206 => <span> 0.0108 mol benzene 
</span>
hope this helps!

6 0
3 years ago
Read 2 more answers
One app charges $3.90 to download and $.79 for each song bought. A second app is free to download and charges $1.09 for each son
Rainbow [258]

Answer:

3.6

Explanation:

7 0
3 years ago
4. What is the volume of a box that has a length of 50cm, a width of 20cm,<br> and a height of 5 cm?
EastWind [94]

5,000 cm3 (cubic centimeters)

4 0
3 years ago
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