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mario62 [17]
3 years ago
13

What is the correct name for the compound p4o6?

Chemistry
1 answer:
Arturiano [62]3 years ago
3 0
Tetraphosphorus Hexoxide
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A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
Aleks [24]

Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

Molarity = \frac{mol}{L}

Molarity of crystal violet = 3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = 3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

The total volume of the solution after mixing NaOH and crystal violet is

0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = \frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}

Final concentration of CV = 0.0027 M

Molarity of NaOH= \frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}

NaOH is a strong base and dissociates completely as follows.

NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0
3 years ago
If a 12 mg metal ring is heated using 30.0 calories, it’s temperature rises 1.9 degrees Celsius. Calculate the specific heat of
notka56 [123]

Answer:

c = 5505263.16 J/g.°C

Explanation:

Given data:

Mass of ring = 12 mg (12/1000 = 0.012 g)

Calories used = 30.0 cal (30.0 ×4184 = 125520 J)

Temperature increases = 1.9°C

Specific heat of ring = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

125520 J = 0.012 g×c ×1.9°C

125520 J = 0.0228 g.°C ×c

c = 125520 J /  0.0228 g.°C

c = 5505263.16 J/g.°C

6 0
3 years ago
Which of the following is true about covalent bonding?
zhenek [66]

Answer:

Electrons are shared in pairs!

Explanation:

I'm doing learning about  Covalent Bonding too:)  

7 0
3 years ago
Using a spectrophotometer, and a cuvette with a path length of 1 cm you measure the absorbance (A275) of Guanosine to be 0.70. C
Anton [14]

Answer : The concentration of guanosine in your sample is, 8.33\times 10^{-5}M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution  = 0.70

C = concentration of solution = ?

l = path length = 1.00 cm

\epsilon = molar absorptivity coefficient guanosine  = 8400M^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

0.70=8400M^{-1}cm^{-1}\times C\times 1.00cm

C=8.33\times 10^{-5}M

Thus, the concentration of guanosine in your sample is, 8.33\times 10^{-5}M

5 0
3 years ago
An unknown substance has a mass of 15.5 g . When the substance absorbs 1.395×102 J of heat, the temperature of the substance is
wlad13 [49]

Answer:

iron (Fe)

Explanation:

Use q = mcΔT.

q = 1.396 x 10^2 J

m = 15.5g

ΔT = (45.0 - 25.0) = 20 degrees celcius

1.396 x 10^2 = 15.5 x c x 20

c = .450 J/g x degrees celcius

This is closest to the specific heat of iron/steel.

4 0
4 years ago
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