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vredina [299]
4 years ago
11

An unknown substance has a mass of 15.5 g . When the substance absorbs 1.395×102 J of heat, the temperature of the substance is

raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?
Chemistry
1 answer:
wlad13 [49]4 years ago
4 0

Answer:

iron (Fe)

Explanation:

Use q = mcΔT.

q = 1.396 x 10^2 J

m = 15.5g

ΔT = (45.0 - 25.0) = 20 degrees celcius

1.396 x 10^2 = 15.5 x c x 20

c = .450 J/g x degrees celcius

This is closest to the specific heat of iron/steel.

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~ WILL MARK AS BRAINLIEST ~
Genrish500 [490]

Answer:

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

Explanation:

Mass of solution = M

Mass percentage of the solution of lime = 15%

Mass of lime or calcium hydroxide = m = 30 g

The Formula of mass percentage is given as :

m/m\%=\frac{m}{M}\times 100

On substituting the values in ab above formula :

15\%=\frac{30 g}{M}\times 100

M=\frac{30 g}{15}\times 100=200 g

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

7 0
3 years ago
How many grams of KBr are present in 250.0mL of a 1.20M solution
castortr0y [4]
Molar mass KBr = 119 g/mol

Volume in liters: 250.0mL / 1000 => 0.25 L

n = M x V

n = 1.20 x 0,25 => 0.3 moles of KBr

Therefore:

1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??

0.3 x 119 / 1 => 35.7 g of KBr 
4 0
3 years ago
Why does CCl4 dissolve in iodine
nirvana33 [79]

Answer: They are both non polar molecules compounds although water is a polar molecule compound. There are no significant attractions.

8 0
3 years ago
Four of the following pairs of acids list the weaker acid at the left and the stronger acid at the right. Which pair is reversed
atroni [7]

Answer:

d. pair

Explanation:

because,H3PO4 is a strong acid

6 0
3 years ago
Using the following information, what are the values of the exponents in the rate expression, rate = k[A]x[B]y
pashok25 [27]

Answer:

The correct option is;

A) x = 2, y = 1

Explanation:

Here we have

k[0.05]^x \cdot [0.05]^y = 0.062 \ M/sec....................(1)

k[0.05]^x \cdot [0.10]^y = 0.123 \ M/sec....................(2)

k[0.100]^x \cdot [0.100]^y = 0.491 \ M/sec  ..............(3)

From experiment (1), (2) it is observed that [A] is held constant and [B] is doubled of which the rate is also observed to be doubled, therefore, when you double a reactant which result in the rate being doubled, the order of the reaction with respect to the reactant is order 1, therefore, y = 1.

Similarly between reaction (2) and (3) when the concentration of the reactant B is doubled and A is held constant the rate of the reaction is multiplied by a factor of 4, therefore, the reaction with respect to that reactant is order 2, therefore, x = 2.

Therefore, the correct option is x = 2, y = 1.

3 0
3 years ago
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