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Ludmilka [50]
3 years ago
11

a sample of H2 is collected over water such that the combined hydrogen water vapor sample is held at a pressure of one standard

atmosphere. what is the partial pressure of the H2 if that of the water vapor is 2.5 kPa
Chemistry
1 answer:
Trava [24]3 years ago
7 0

Answer : The partial pressure of H_2 is 98.825 kPa.

Solution : Given,

Total pressure of hydrogen water vapor = 1 atm = 101.325 kPa    (1 atm = 101.325 kPa)

Partial pressure of water vapor = 2.5 kPa

Dalton's law of partial pressure : It is defined as the total pressure exerted is equal to the sum of the partial pressure of individual gases.

Formula used :

P_{Total}=\sum_{i=1}^nP_i

P_{Total} = Total pressure

P_{i} = Partial pressure of individual gases

P_{Total}=P_{H_2}+P_{\text{ Water vapor}}

Now put all the given values in this expression, we get

101.325kPa=P_{H_2}+2.5kPa

P_{H_2}=98.825kPa

Therefore, the partial pressure of H_2 is 98.825 kPa.

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Answer:

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Explanation:

To solve this question you need to understand that part of Raoult's law in your Chemistry textbook. So, let us delve right into the solution of the question.

We are given parameters such as the mass of Ca(OH)2 to be = 11.1 grams, mass of solvent = 102 grams, the Vapor pressure of pure water= 23.76 mm Hg, temperature = 25°C and vapour pressure of the solution= ??.

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The first thing to do is to find the number of moles of Ca(OH)2 and that of water from the formula below;

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Number of moles, n= 5.67 moles of water.

Next, we add the two moles together to find the solvent mile fraction since vapour pressure is proportional to mole fraction.

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0.15 + 5.67 = 5.82.

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Hence the vapor pressure of a solution = 0.97 × 23.76.

vapor pressure of a solution = 23.15 mmHg.

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