Answer:
Newton's law of inertia - His first law states that every object remains at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... This is the first part cited in Newton's first law; "there is no net force on the airplane and it travels at a constant velocity in a straight line."
Newton's law of acceleration - "a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity."
Newton's law of Action/Reaction - "As a plane flies, the force of the air hitting the plane is always equal and opposite to the force of the plane pushing against the air. The force generated by the engine pushes against air while the air pushes back with an equal and opposite force."
Hope this helps! god bless :)
Please give me brainliest!
They should look for <span>a report from an independent scientific research firm,
even if they have to pay for it.
In preparing its report, the firm would have already surveyed many of the </span>
<span>citizens from several other towns that currently add fluoride to their water,
plus a lot of other relevant medical research on the subject.</span>
Answer:
51 Ω.
Explanation:
We'll begin by calculating the equivalent resistance of R₁ and R₃. This can be obtained as follow:
Resistor 1 (R₁) = 40 Ω
Resistor 3 (R₃) = 70.8 Ω
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) =?
Since the two resistors are in parallel connection, their equivalent can be obtained as follow:
R₁ₙ₃ = R₁ × R₃ / R₁ + R₃
R₁ₙ₃ = 40 × 70.8 / 40 + 70.8
R₁ₙ₃ = 2832 / 110.8
R₁ₙ₃ = 25.6 Ω
Finally, we shall determine the equivalent resistance of the group. This can be obtained as follow:
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) = 25.6 Ω
Resistor 2 (R₂) = 25.4 Ω
Equivalent Resistance (Rₑq) =?
Rₑq = R₁ₙ₃ + R₂ (series connection)
Rₑq = 25.6 + 25.4
Rₑq = 51 Ω
Therefore, the equivalent resistance of the group is 51 Ω.
Answer:
Humus
Explanation:
Its Humus I believe. I remember learning something like this.
Answer:
The change in potential energy is ![\Delta PE = - 3.8*10^{-16} \ J](https://tex.z-dn.net/?f=%5CDelta%20%20PE%20%3D%20%20-%20%203.8%2A10%5E%7B-16%7D%20%5C%20J)
Explanation:
From the question we are told that
The magnitude of the uniform electric field is ![E = 950 \ N/C](https://tex.z-dn.net/?f=E%20%3D%20%20950%20%5C%20N%2FC)
The distance traveled by the electron is ![x = 2.50 \ m](https://tex.z-dn.net/?f=x%20%3D%20%202.50%20%5C%20m)
Generally the force on this electron is mathematically represented as
Where F is the force and q is the charge on the electron which is a constant value of ![q = 1.60*10^{-19} \ C](https://tex.z-dn.net/?f=q%20%3D%20%201.60%2A10%5E%7B-19%7D%20%5C%20C)
Thus
![F = 950 * 1.60 **10^{-19}](https://tex.z-dn.net/?f=F%20%20%3D%20%20950%20%20%2A%201.60%20%2A%2A10%5E%7B-19%7D)
![F = 1.52 *10^{-16} \ N](https://tex.z-dn.net/?f=F%20%20%3D%201.52%20%2A10%5E%7B-16%7D%20%5C%20N)
Generally the work energy theorem can be mathematically represented as
![W = \Delta KE](https://tex.z-dn.net/?f=W%20%3D%20%20%5CDelta%20%20KE)
Where W is the workdone on the electron by the Electric field and
is the change in kinetic energy
Also workdone on the electron can also be represented as
Where
considering that the movement of the electron is along the x-axis
So
![\Delta KE = F * x cos (0)](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%3D%20%20F%20%20%2A%20x%20%20cos%20%20%280%29)
substituting values
![\Delta KE = 1.52 *10^{-16} * 2.50 cos (0)](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%3D%20%201.52%20%2A10%5E%7B-16%7D%20%20%2A%202.50%20%20%20cos%20%20%280%29)
![\Delta KE = 3.8*10^{-16} J](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%20%3D%20%203.8%2A10%5E%7B-16%7D%20J)
Now From the law of energy conservation
Where
is the change in potential energy
Thus
![\Delta PE = - 3.8*10^{-16} \ J](https://tex.z-dn.net/?f=%5CDelta%20%20PE%20%3D%20%20-%20%203.8%2A10%5E%7B-16%7D%20%5C%20J)