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cestrela7 [59]
2 years ago
7

What is an analogy that describes the process of electron carriers?

Physics
2 answers:
Sedaia [141]2 years ago
7 0
<h3><u>Answer;</u></h3>

The analogy that describes the process of electron carriers is<em><u> the oven mitt and hot potato analogy</u></em>

<h3><u>Explanation;</u></h3>
  • <em><u>Electron carriers are used to transport the electrons from chlorophyll to other molecules during the process of photosynthesis which takes place in plants.</u></em>
  • <u><em>The analogy that describes the process of electron carriers is hot potato and an oven mit; such that the hot potato represents 2 high energy electrons.</em></u>
  • <em><u>According to the analogy the  NADP+ is the carrier molecule that transports pairs of electrons (and an H+ ion) in photosynthetic organisms, similar to how an oven mitt is used to transport a hot object such as a hot potato.</u></em>
Vladimir79 [104]2 years ago
4 0
<span>An analogy is a comparison between one thing and another, typically for the purpose of explanation or clarification.</span><span>

An analogy of an electron carrier molecule and high energy electrons can be just like moving a potato. </span>A laundry basket filled with warm laundry can also be compared to an electron carrier. In this analogy, the laundry basket represents the electron carrier and the warm laundry represents the high energy electrons. There is another analogy that describes the process of electron carriers is a laundry basket filled with warm laundry can also be compared to an electron carrier. In this analogy, the laundry basket represents the electron carrier and the warm laundry represents the high energy electrons.  
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The gravitational force between two objects is proportional to the square of the distance between the two objects.
Darina [25.2K]

Answer: True!

Explanation: The force is proportional to the square of the distance between 2 point masses

3 0
2 years ago
Two resistors, R1=3.85 Ω and R2=6.47 Ω , are connected in series to a battery with an EMF of 24.0 V and negligible internal resi
Bond [772]

Answer:

(a) 2.33 A

(b) 15.075 V

Explanation:

From the question,

The total resistance (Rt) = R1+R2 = 3.85+6.47

R(t) = 10.32 ohms.

Applying ohm's law,

V = IR(t)..........equation 1

Where V = Emf of the battery, I = current flowing through the circuit, R(t) = combined resistance of both resistors.

Note: Since both resistors are connected in series, the current flowing through them is the same.

Therefore,

I = V/R(t)............. Equation 2

Given: V = 24 V, R(t) = 10.32 ohms

Substitute these values into equation 2

I = 24/10.32

I = 2.33 A.

Hence the current through R1 = 2.33 A.

V2 = IR2.............. Equation 3

V2 = 2.33(6.47)

V2 = 15.075 V

7 0
3 years ago
650 N boy and a 419 N girl sit on a 150 N porch swing that is 2.0 m long. If the swing is supported by a chain at each end, what
Sergio039 [100]

The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

<h3>Principle of moments</h3>

The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.

The formula for calculating moment is given below:

  • Moment = Force × perpendicular distance from the pivot

<h3>Calculating the tension in the chains</h3>

From the principle of moments:

Let tension in chain 1 be T1 and tension in chain 2 be T2.

T1 + T2 = 150 + 650 + 419

T1 + T2 =1219

Taking all distances from chain 1,

Sum of Moments = 0

419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7

T2 = 922/17

T2 = 542.35 N

Then, T1 = 1219 - 542.35

T1 = 676.65 N

Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.

Learn more about tension and moments at: brainly.com/question/187404

brainly.com/question/14303536

7 0
2 years ago
An 85.0 kg fisherman jumps from a dock at a speed of 4.30 m/s onto their 135.0 kg boat. If the boat was at rest to begin but mov
jeka94

Answer:

Final speed of boat + man is 1.66 m/s

Explanation:

As we know that there is no friction on the system or there is no external force on this system

So here we can use momentum conservation here

mv = (m + M)v_f

so we have

m = 85 kg

M = 135 kg

v = 4.30 m/s

now we have

85 \times 4.30 = (85 + 135) v

v = 1.66 m/s

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Explanation:

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