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Scrat [10]
3 years ago
15

15. A travelling wave is described by the equation y(x,t)= 0.003 cos (20 x + 200t) where y and x are

Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

T = 3.14 10⁻²  s

Explanation:

The general equation for a traveling transverse wave is

           y = A sin (k x - wt +Ф)

where w is the angular velocity that is related to the period and Ф is the phase of the oscillation

           w = 2π / T          (1)

In this case they indicate that the expression of the wave

         y = 0.003 cos (20 x + 200t)

if we use the relationship of the double angles

          a = kx - wt

          b = Ф

          sin (a + b) = sin a cos b + sin b cos a

for the case Ф = 90 we have

          sin (a + b) = cos b

we substitute

          y = A cos (kx -wt)

with an initial phase of fi = 90º

if we compare the terms of the two expressions

         A = 0.003 m  

         k = 20 m⁻¹

         w = -200  rad/s

the negative sign indicates that the wave goes to the left

           

if we clear from equation 1

          T = 2π / w

          T = 2π / 200

          T = 3.14 10⁻²  s

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3 years ago
What happens to the acceleration of an object if the net force that acts on it triples in magnitude?
poizon [28]

F=ma Force is equal to mass times acceleration.


So looking at the equation if mass stays the same but we make F three times larger then acceleration will become 3 times larger as well because the equation must remain equal on both sides.


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5 0
4 years ago
An object oscillates with an angular frequency of 8.0 rad/s. At t = 0, the object is at x0 = 4 cm with an initial velocity v0 =
KatRina [158]

Answer:

\phi = 0.66 rad

A = 5.06 cm

Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:  

x(t)=Acos(\omega t+\phi) (1)

A: Amplitude

ω: angular frequency

φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi) (2)

Let's evaluate (1) and (2) in t=0.

x(0)=Acos(\phi) (3)

v(0)=-A\omega sin(\phi) (4)

Dividing 4 by 3 we have:

\frac{v(0)}{x(0)}=-\omega tan(\phi)

\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})

\phi = 0.66 rad

Now, using (3) we can find the amplitude.

A = \frac{x(0)}{cos(\phi)} = 5.06 cm

I hope it helps!                            

6 0
4 years ago
In order to remove water from a flooded basement, two pumps, each rated at 45 gallons per minute, are used. After half an hour,
LenKa [72]

Answer:

4050 gallons

Explanation:

In first half and hour both pumps are working property . There for it give, 45

gallons per minute . Half and hour is equal to 30 minutes.After one pump was broken only one pump is working 30 minutes .

For 1st 30 minutes ,( 2 pumps are working )

Gallons = 45 * 30 *2 = 2700 gallons

2nd 30 minutes ( 1 pump is working )

Gallons = 45*30*1 = 1350 gallons

Total gallons = 2700+1350

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A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?
natulia [17]
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A.17 s


B.0.058 s


C.0.25 s


D.2.0 s
7 0
3 years ago
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