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Firdavs [7]
3 years ago
7

Identify the ways in which carbon is added to the atmosphere?

Physics
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer:

Decay organisms, dead organisms and waste products, root respiration, animal respiration, plant respiration and factory emission.

Explanation:

Carbon cycle is one of the biogeochemical cycle in which the different forms of carbon circulates in the biosphere, atmosphere, lithosphere, hydrosphere and pedosphere. In the given situation, the the process of photosynthesis will take up the carbon dioxide from the atmosphere. But other processes like decay organisms, dead organisms and waste products, root respiration, animal respiration, plant respiration and factor emission will add carbon to the atmosphere.

The decay and dead organisms and their waste products: These dead organisms will be decayed by the soil microbes which will produce organic carbon matter in the soil. This organic carbon will be liberated into the atmosphere as carbon dioxide.

Root respiration: The roots are the underground parts of the plant which does not receive oxygen directly from air instead they receive oxygen which is present in the soil pores. The respiration process produces carbon dioxide as product which is released into the atmosphere.

Plant respiration: Plants have small pores called as stomata present on the surface of their leaves. The plants receives oxygen through these pores and expel out carbon dioxide into the atmosphere.

Animal respiration: The animals have prominent and complex respiratory system. The animals take oxygen from the air and expel out carbon dioxide.

Factory emission: Factories use fossil fuels for the generation of electricity. The burning of the fossil fuels liberate carbon gases such as carbon dioxide and carbon monoxide into the atmosphere.

sashaice [31]3 years ago
6 0
Animal respiration, dead organisms, decay organisms and factory emmissions<span />
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Answer:

\frac{1}{\sqrt{2}}

Explanation:

The speed of a wave in a string is given by:

v=\sqrt{\frac{T}{m/L}}

where

T is the tension in the string

m is the mass of the string

L is the length

In this problem, the mass of the string is increased to 2m: m' = 2 m, while the length is not changed, L'=L. If the tension in the string is not changed, then the new speed of the wave in the string will be:

v'=\sqrt{\frac{T}{m'/L'}}=\sqrt{\frac{T}{2m/L}}=\frac{1}{\sqrt{2}}\sqrt{\frac{T}{m/L}}=\frac{v}{\sqrt{2}}

so, the speed of the wave decreases by a factor \frac{1}{\sqrt{2}}

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