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arlik [135]
3 years ago
14

Find the height of a trapezoid if b1= 2x + 1 and b2 = x+4 and the area = 3x2 + 5x Show all your work for full credit.

Mathematics
1 answer:
Advocard [28]3 years ago
5 0
A = 1/2 h (b1+b2)
so
h = 2A / (b1+b2)
h = [2(3x^2 + 5x)] / (2x + 1 + <span>x + 4)
h = (6x^2 + 10x)/(3x +5)
h = 2x(3x + 5)/(3x +5)
h = 2x

answer: </span><span>height of a trapezoid = 2x</span>
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ANTONII [103]

Answer: 9b+4n+6d+7

Step-by-step explanation:

1. 9b+9+4n−4+6d+2

2. 9b+4n+6d+(9-4+2)

3. 9b+4n+6d+7

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Which statements are true? Select three options. ∠F corresponds to ∠F'. Segment EE' is parallel to segment FF'. The distance fro
Gwar [14]

Answer:

The correct options are (1), (3) and (5).

Step-by-step explanation:

The two triangles are shown below.

The measure of ∠F corresponds to ∠F'.

The distance between the points D and origin is of 9 units.

And the distance between the points D' and origin is 3 units.

Thus, the distance from point D' to the origin is One-third the distance of point D to the origin.

Check for similarity:

\frac{D'F'}{DF}=\frac{D'E'}{DE}=\frac{F'E'}{FE}=\frac{1}{3}

Thus, the △DEF is similar to △D'E'F'.

Thus, the correct options are (1), (3) and (5).

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Solve The Quadratic Equation by the Square Root Method.<br><br> (x - 2)^2-1=0
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3 years ago
-6x-14y=-20<br> -3x-7y=-10
Alex Ar [27]
ANSWER:

x = 10 / 3

y = 0

STEP-BY-STEP EXPLANATION:

We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.

Equation No. 1 -

- 6x - 14y = - 20

Equation No. 2 -

- 3x - 7y = - 10

First, we will make ( x ) the subject in the first equation and simplify accordingly.

Equation No. 1 -

- 6x - 14y = - 20

- 6x = - 20 + 14y

x = ( - 20 + 14y ) / - 6

x = ( - 10 + 7y ) / - 3

From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.

Equation No. 2 -

- 3x - 7y = - 10

- 7y = - 10 + 3x

- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]

- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]

- 7y = - 10 + ( 10 - 7y )

- 7y = - 7y

- 7y + 7y = 0

0y = 0

y = 0

Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.

x = ( - 10 + 7y ) / - 3

x = [ - 10 + 7 ( 0 ) ] / - 3

x = [ - 10 + 0 ] / - 3

x = - 10 / - 3

x = 10 / 3
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