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Pani-rosa [81]
3 years ago
14

What is the answer to the variable x in the multi-step problem 8x-6=2x-6+6x

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

All real numbers are solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

8x−6=2x−6+6x

Step 1: Simplify both sides of the equation.

8x−6=2x−6+6x

8x+−6=2x+−6+6x

8x−6=(2x+6x)+(−6)(Combine Like Terms)

8x−6=8x+−6

8x−6=8x−6

Step 2: Subtract 8x from both sides.

8x−6−8x=8x−6−8x

−6=−6

Step 3: Add 6 to both sides.

−6+6=−6+6

0=0

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notsponge [240]
11.196 or 11.20 is the answer
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3 years ago
Y - (-8) &gt; -12 = ?<br><br> im slow
OLga [1]

Answer:

(-8,-2) (-4,6)

Step-by-step explanation:i just got the answer

4 0
2 years ago
64. In a pond of 1,600 fish, 25% of the fish are trout. The remaining fish are bass. How fewer trout are there than bass?
Nina [5.8K]

Answer:

There are 400 trout and 1,200 of them are bass.

4 0
3 years ago
Read 2 more answers
(Algebra II) Standard Form of a Quadratic Function - I'm having trouble with two questions on this quiz? Please don't just give
anastassius [24]
1.
the x value of the vertex in form
ax^2+bx+c=y
is
-b/2a
so

-2x^2+8x-18
x value of vertex is
-8/(2*-2)=-8/-4=2

plug it in to get y value
-2(2)^2+8(2)-18
-2(4)+16-18
-8-2
-10

vertex is at (2,-10)
or you could complete the square to get into y=a(x-h)^2+k, where the vertex is (h,k)
so as follows
y=(-2x^2+8x)-18
y=-2(x^2-4x)-18
y=-2(x^2-4x+4-4)-18
y=-2((x-2)^2-4)-18
y=-2(x-2)^2+8-18
y=-2(x-2)^2-10
vertex is (2,-10)






5.
vertex is the time where the speed is the highest
at about t=10, the speed is at its max
6 0
3 years ago
Read 2 more answers
The formula for a trapezoid relates the area A, the two bases, a and b, and the height, h. A=(a+b)/2 h Solve for a.
yKpoI14uk [10]

Answer:

a=\frac{2A}{h}-b

Step-by-step explanation:

Hello, I think I can help you with this.

According to the information provided in the problem, the area of ​​a trapezoid is given by

A=\frac{a+b}{2} *h\\

Step 1

solve for a, it means isolate a

A=\frac{a+b}{2} *h\\divide\ both\ sides\ by\ h\\\\\frac{A}{h}= \frac{\frac{a+b}{2} *h}{h} \\\frac{A}{h}=\frac{a+b}{2}\\\\Now, multiply\ both\ sides\ by\ two\\\\ 2*\frac{A}{h}=2*\frac{a+b}{2}\\2*\frac{A}{h}=a+b\\\frac{2A}{h}=a+b\\\\subtract\ b\ for\ both\ sides\\\frac{2A}{h}-b=a+b-b\\a=\frac{2A}{h}-b

Have a good day.

5 0
3 years ago
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